我尝试上传的文件始终是xml文件。我想将content-type设置为application / xml 这是我的代码:
MultiValueMap<String, Object parts = new LinkedMultiValueMap<String,
Object(); parts.add("subject", "some info");
ByteArrayResource xmlFile = new ByteArrayResource(stringWithXMLcontent.getBytes("UTF-8")){
@Override
public String getFilename(){
return documentName;
}
};
parts.add("attachment", xmlFile);
//sending the request using RestTemplate template;, the request is successfull
String result = template.postForObject(getRestURI(), httpEntity,String.class);
//but the content-type of file is 'application/octet-stream'
原始请求如下所示:
Content-Type:
multipart/form-data;boundary=gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz
User-Agent: Java/1.7.0_67 Host: some.host Connection: keep-alive
Content-Length: 202866
--gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz Content-Disposition: form-data; name="subject" Content-Type: text/plain;charset=ISO-8859-1
Content-Length: 19
some info
--gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz Content-Disposition: form-data; name="attachment"; filename="filename.xml" Content-Type:
application/octet-stream Content-Length: 201402
....xml file contents here ..
正在生成文件的内容类型为&#39; application / octet-stream&#39;我希望它在哪里&#39; application / xml&#39; 如何设置文件的内容类型?
答案 0 :(得分:30)
我从这个链接中提示后找出了解决方案:
Making a multipart post request with compressed jpeg byte array with spring for android
解决方法是将ByteArrayResource放在带有必需标头的HttpEntity中,并将HttpEntity添加到Multivaluemap(而不是添加ByteArrayResource本身。)
代码:
Resource xmlFile = new ByteArrayResource(stringWithXMLcontent.getBytes("UTF-8")){
@Override
public String getFilename(){
return documentName;
}
};
HttpHeaders xmlHeaders = new HttpHeaders();
xmlHeaders.setContentType(MediaType.APPLICATION_XML);
HttpEntity<Resource> xmlEntity = new HttpEntity<Resource>(xmlFile, xmlHeaders);
parts.add("attachment", xmlEntity);
答案 1 :(得分:0)
我没有使用RestTemplate,但我过去使用过HttpClient - 这就是我传递身体部位的方法 -
MultipartEntityBuilder eb = MultipartEntityBuilder.create().setBoundary(MULTIPART_BOUNDARY)
.addTextBody(BODYPART_ENTITY, key, ContentType.create("application/xml", Charset.forName("UTF-8")));
您必须查看RestTemplate中的API,它可以采用内容类型
答案 2 :(得分:0)
由于我无法评论@RGR的答案,因此我将其发布为新答案,尽管RGR的答案绝对正确。
问题是Sprint RestTemplates使用FormHttpMessageConverter发送多部分请求。此转换器检测从资源继承的所有内容,并将其用作请求的“文件”部分。 例如如果您使用MultiValueMap,则添加的每个属性都会在添加“资源”后立即发送给它自己的部分。->设置文件名,Mime-Type,长度,..将不属于“文件”部分”。
不是答案,但这是为什么必须扩展ByteArrayResource以返回文件名并作为请求的唯一部分发送的原因。发送多个文件将与MultiValueMap一起使用
似乎在Spring 4.3中解决了此问题答案 3 :(得分:0)
这是我处理文件上传和接收上传文件的方式:
public String uploadFile(byte[] fileContent, String contentType, String filename) {
String url = "https://localhost:8000/upload";
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
MultiValueMap<String, String> fileMap = new LinkedMultiValueMap<>();
ContentDisposition contentDisposition = ContentDisposition.builder("form-data")
.name("file")
.filename(filename)
.build();
fileMap.add(HttpHeaders.CONTENT_DISPOSITION, contentDisposition.toString());
fileMap.add(HttpHeaders.CONTENT_TYPE, contentType);
HttpEntity<byte[]> entity = new HttpEntity<>(fileContent, fileMap);
MultiValueMap<String, Object> body = new LinkedMultiValueMap<>();
body.add("file", entity);
HttpEntity<MultiValueMap<String, Object>> requestEntity = new HttpEntity<>(body, headers);
ResponseEntity<String> response = template.exchange(url, HttpMethod.POST, requestEntity, String.class);
return response.getBody();
}
我通过在端口8000上监听的服务来消耗它:
@Controller
@RequestMapping("upload")
public class FileUploadController {
@PostMapping("")
public ResponseEntity uploadFile(@RequestParam("file") MultipartFile file) {
handleUploadedFile(
file.getSize(),
file.getBytes(),
file.getContentType(),
file.getOriginalFilename()
);
}
}