Question

我有这些数据:(完成Dicember）

      date     sessions
1   2014-12-01  1932
2   2014-12-02  1828
3   2014-12-03  2349
4   2014-12-04  8192
5   2014-12-05  3188
6   2014-12-06  3277

需要对此进行subet /过滤，例如来自＆＃34; 2014-12-05＆＃34;到＆＃34; 2014-12-25＆＃34;

我现在可以使用运算符＆＃34;：＆＃34;创建序列。

示例：b＆lt; - c（1：5）

但如何过滤序列？我试过这个

NewDate <- filter(Dates, date("2014-12-05":"2014-12-12"))

但是说：

错误：意外符号：＆＃34; NewDate＆lt; - 过滤器（日期，日期（＆＃34; 2014-12-05＆＃34;：＆＃34; 2014-12-12＆＃34;） NewDate＆＃34;

Answer 1

如果您想使用dplyr，可以尝试这样的事情。

mydf <- structure(list(date = structure(c(16405, 16406, 16407, 16408, 
16409, 16410), class = "Date"), sessions = c(1932L, 1828L, 2349L, 
8192L, 3188L, 3277L)), .Names = c("date", "sessions"), row.names = c("1", 
"2", "3", "4", "5", "6"), class = "data.frame")

# Create date object
mydf$date <- as.Date(mydf$date) 

filter(mydf, between(date, as.Date("2014-12-02"), as.Date("2014-12-05")))

#If you avoid using `between()`, the code is simpler.

filter(mydf, date >= "2014-12-02", date <= "2014-12-05")
filter(mydf, date >= "2014-12-02" & date <= "2014-12-05")

#        date sessions
#1 2014-12-02     1828
#2 2014-12-03     2349
#3 2014-12-04     8192
#4 2014-12-05     3188

Answer 2

您可以使用subset

生成示例数据：

temp<-
read.table(text="date     sessions
2014-12-01  1932
2014-12-02  1828
2014-12-03  2349
2014-12-04  8192
2014-12-05  3188
2014-12-06  3277", header=T)

确保它采用日期格式：

temp$date <- as.Date(temp$date, format= "%Y-%m-%d")

temp



 #        date sessions
 # 1 2014-12-01     1932
 # 2 2014-12-02     1828
 # 3 2014-12-03     2349
 # 4 2014-12-04     8192
 # 5 2014-12-05     3188
 # 6 2014-12-06     3277

使用subset：

subset(temp, date> "2014-12-03" & date < "2014-12-05")

给出：

  #        date sessions
  # 4 2014-12-04     8192

你也可以使用[]：

temp[(temp$date> "2014-12-03" & temp$date < "2014-12-05"),]

Answer 3

使用data.table

的选项

 library(data.table)
 setDT(df)[date %between% c('2014-12-02', '2014-12-05')]
 #         date sessions
 #1: 2014-12-02     1828
 #2: 2014-12-03     2349
 #3: 2014-12-04     8192
 #4: 2014-12-05     3188

即使＆＃34; date＆＃34;是＆＃34;字符＆＃34;柱

 df$date <- as.character(df$date)
 setDT(df)[date %between% c('2014-12-02', '2014-12-05')]
 #       date sessions
 #1: 2014-12-02     1828
 #2: 2014-12-03     2349
 #3: 2014-12-04     8192
 #4: 2014-12-05     3188

如果我们想要排除范围

的子集

  setDT(df)[between(date, '2014-12-02', '2014-12-05', incbounds=FALSE)]
  #         date sessions
  #1:  2014-12-03     2349
  #2:  2014-12-04     8192

数据

 df <-  structure(list(date = structure(c(16405, 16406, 16407, 16408, 
 16409, 16410), class = "Date"), sessions = c(1932L, 1828L, 2349L, 
 8192L, 3188L, 3277L)), .Names = c("date", "sessions"), row.names = c("1", 
 "2", "3", "4", "5", "6"), class = "data.frame")

Answer 4

使用lubridate，

mydates <- interval(start = "2014-12-05", end = "2014-12-25")
NewDate <- Dates[which(date %within% mydates),]

R：如何过滤/子集一系列日期

4 个答案:

数据