Question

自昨晚以来一直无所事事。但

createOrder($website,(int)$nVotes,(int)$timeframe,$loggedInUser->email,$server,(int)$start,$referer);

var_dumping这些变量显示（早先）：

string（2）＆＃34; web1＆＃34;字符串（2）＆＃34; 10＆＃34;字符串（2）＆＃34; 10＆＃34;串（23）＆＃34; myemail@gmail.com" string（8）＆＃34; myserver＆＃34; int（1423063633）string（17）＆＃34; http://google.com＆＃34;

和似乎有问题的功能是：

function createOrder($website,$votes,$timeframe,$user,$server,$start,$referer)
{
    global $mysqli,$db_table_prefix;
    $time = time();
    $stmt = $mysqli->prepare("INSERT INTO ".$db_table_prefix."orders (
        serverId,
        orderUser,
        targetUrl,
        nVotes,
        timeframe,
        referer,
        starting
        )
        VALUES (
        ?,
        ?,
        ?,
        ?,
        ?,
        ?,
        ?
        )");
    file_put_contents("error.log", $mysqli->errno . $mysqli->error );
    $stmt->bind_param("sssiisi", $server, $user, $website, $votes, $timeframe, $referer, $start);
    file_put_contents("error1.log", $stmt->errno . $stmt->error );
    $stmt->execute();
    file_put_contents("error1.log", $stmt->errno . $stmt->error );
    $stmt->close();

nginx.error.log归咎于bind_param

＆＃34; PHP消息：PHP致命错误：调用成员函数第1223行funcs.php中非对象的bind_param（）

error.log归咎于语法错误

(check the manual) for the syntax to use near 'starting

  )
                VALUES (
                ?,
                ?,
                ?,
                ?,
                ?,
                ?,
                ?
                )' at line 8

Answer 1

问题是starting是reserved word in MySQL，您将其用作字段名称。你应该用反引号包装它：

    serverId,
    orderUser,
    targetUrl,
    nVotes,
    timeframe,
    referer,
    `starting`

语法错误与准备好的语句mysql / php

1 个答案: