如何在弹出窗口中设置按钮以垂直显示

Question

为此，我的代码是

- (int)ldapAlertMessage:(NSString *)alertMessage
{
    int x=0;
    if (nil != alertMessage) {
        NSImage *alertIcon = [NSImage imageNamed:@"security_alert_icon"];
        NSAlert *alert = [[NSAlert alloc]init];
        [alert addButtonWithTitle:@"Yes"];
        [alert addButtonWithTitle:@"No"];
         [alert addButtonWithTitle:@"Cancel"];
        [alert setMessageText:alertMessage];
        [alert setAlertStyle:NSWarningAlertStyle];
        [alert setIcon:alertIcon];
        [[alert window] setBackgroundColor: NSColor.whiteColor];
        int result= [alert runModal];
        switch(result)
        {
    case NSAlertFirstButtonReturn:
            {
                x=1;
                return x;
                break;
            }
    case NSAlertSecondButtonReturn:
            {
                x=2;
                return x;
                break;
            }

            case NSAlertThirdButtonReturn:
            {
                x=3;
                return x;
                break;
            }

        }
           }

    return x;

}

使用

调用

   user_response = [self ldapAlertMessage: @"You will no longer be able to access your ldap login on this device if you select this."];

根据按钮执行时定义的用户响应操作。

我想要一种方法来了解如何让我的按钮垂直显示，因为我会更改文本是，不会更大。