Question

我已经在这里阅读了几个小时的类似问题，而我似乎无法得到它。我对java很有经验，但这是我在C中的第一个项目。教授完全没有教我们这个项目的相关技能。

程序目的：从文本文件中一次读取一对文本行，并根据ASCII整理顺序确定第一个是否等于，大于或小于第二个。程序还将指示出现第一个偏差的字符位置。程序将处理所有线对，然后打印处理的对的总数，即数字等对，第一行的数量大于第二行，第一行的数量小于第二行的数量。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void readFile(char **strs){


    //read strings from file and place them in strs

}

void comparePairs(char *strs, int *nums){
    //compares pairs of strings according to ASCII collating sequence, 
    //printing strings as it goes. Also prints the position of the first deviation
    //between a pair, if there is any. 
    //returns numPairs, numEqual, numGreater, and numLesser
    int numPairs = 0;
    int numEqual = 0, numGreater = 0, numLesser = 0; 

    nums[0] = numPairs;
    nums[1] = numEqual;
    nums[2] = numGreater;
    nums[3] = numLesser;
}

void printResults(int numPairs, int numEqual, int numGreater, int numLesser){
    printf("%d pairs were processed.\n", numPairs);
    printf("%d equal pair(s).\n", numEqual);
    print("%d greater pair(s).\n", numGreater);
    print("%d less than pairs(s).\n", numLesser);
}

int main(){
    char strs[100][1000];//strings from file (max 100 strings, each of max size 1000)
    char (*ptrStrs)[1000];
    ptrStrs = strs;
    int nums[4] = {0,0,0,0};//contains numPairs, numEqual, numGreater, and numLesser

    int numPairs = 0;//the total number of pairs processed
    int *ptrNumPairs = &numPairs;

    //the number of pairs where the first line is equal to, greater than, or lesser
    //than the first line respectively
    int numEqual = 0, numGreater = 0, numLesser = 0; 
    int *ptrNumEqual = &numEqual, *ptrNumGreater = &numGreater, *ptrNumLesser = &numLesser; 

    readFile(**strs);
    comparePairs(strs, nums);
    printResults(nums[0], nums[1], nums[2], nums[3]);

    return 0;
}

我收到很多错误，但第一个是passing argument 1 of 'readFile' makes pointer from integer without a cast。任何有助于取得一些进展的帮助将不胜感激。

将2D数组传递给C中的函数

0 个答案: