Question

我将一系列xml文件放在2个单独的文件夹中，如下所示。我的目标是从两个文件夹中一次读取一个文件并应用xmlunit comaprison方法。

Folder1：actual1.xml actual2.xml actual3.xml

Folder2：compare1.xml compare2.xml compare3.xml

第1部分：使用下面的脚本从两个文件夹一次读取每个文件。如果有更简单的方法可以做到这一点，我欢迎提出建议

log.info "**********Read files from Folder1************"
def xml_file1 = []  
new File("D:\\GroovyTest\\Folder1").eachFile{ f ->  
f (f.isFile()&& f.name.contains('.xml'))  
{  
def filename = f.name[0..-1]  
xml_file1.add(filename)  
log.info filename  
}  
}
if (xml_file1.size() <1)  
{  
testRunner.fail("No request files found")  
}

log.info "**********Read files from Folder2************"

def xml_file2 = []  
new File("D:\\GroovyTest\\Folder2").eachFile{ f ->  
if (f.isFile()&& f.name.contains('.xml'))  
{  
def filename = f.name[0..-1]  
xml_file2.add(filename)  
log.info filename  
}  
}  
if (xml_file2.size() <1)  
{  
testRunner.fail("No request files found")  
}

第2部分：对数组xml_file1和xml_file2中包含的每个xml文件组合进行比较的脚本。

实际上，如果每个xml文件都保存在一个字符串中，下面的脚本适用于单个文件，实际上是停留在这个部分，但我必须传递一个数组作为参数，因为我有一系列要比较的xml文件。我得到一个运行时错误 - groovy.lang.GroovyRuntimeException：找不到匹配的构造函数：java.io.FileInputStream（java.util.ArrayList）错误在行：60

InputStream xml_stream1 = new FileInputStream(xml_file1)  
String xml1 = getStringFromInputStream(xml_stream1)  
InputStream xml_stream2 = new FileInputStream(xml_file2)  
String xml2 = getStringFromInputStream(xml_stream2)  
def factory = TransformerFactory.newInstance()  
def transformer = factory.newTransformer(new StreamSource(new StringReader(xslt)))  
StreamResult result_xml1 = new StreamResult(new StringWriter());  
transformer.transform(new StreamSource(new StringReader(xml1)), result_xml1)  
xml1 = result_xml1.getWriter().toString()  
StreamResult result_xml2 = new   StreamResult(newStringWriter());  
transformer.transform(new StreamSource(new StringReader(xml2)), result_xml2)  
xml2 = result_xml2.getWriter().toString()  
XMLUnit.setIgnoreComments(true)  
DifferenceListener differenceListener = newIgnoreTextAndAttributeValuesDifferenceListener();  
DetailedDiff myDiff = new DetailedDiff(new Diff(xml1, xml2));  
myDiff.overrideDifferenceListener(differenceListener);  
myDiff.overrideElementQualifier(new RecursiveElementNameAndTextQualifier());  
log.info "similar ? " + myDiff.similar()  
log.info "identical ? " + myDiff.identical()  
List allDifferences = myDiff.getAllDifferences();  
for (Object object : allDifferences) {  
Difference difference = (Difference)object;  
log.info(difference);  
}

在比较期间，有人还可以帮我找到忽略空标签的方法吗？感谢

Groovy脚本从2个文件夹中一次读取多个xml文件并应用xmlunit比较方法

0 个答案: