Question

我有一个SQLite数据库，它有一个整数列来存储unix时间戳，我需要能够在特定的日子里查询这个列。

我正在寻找一种方法来返回给定日期开始和结束的Unix时间。做这个的最好方式是什么？

Answer 1

这是一种方法。

public long getStartOfDayInMillis() {
    Calendar calendar = Calendar.getInstance();
    calendar.set(Calendar.HOUR_OF_DAY, 0);
    calendar.set(Calendar.MINUTE, 0);
    calendar.set(Calendar.SECOND, 0);
    calendar.set(Calendar.MILLISECOND, 0);
    return calendar.getTimeInMillis();
}

public long getEndOfDayInMillis() {
    // Add one day's time to the beginning of the day.
    // 24 hours * 60 minutes * 60 seconds * 1000 milliseconds = 1 day
    return getStartOfDayInMillis() + (24 * 60 * 60 * 1000);
}

如果您想要特定日期的时间，可以修改代码来处理它。

/**
 * @param date the date in the format "yyyy-MM-dd"
 */
public long getStartOfDayInMillis(String date) throws ParseException {
    SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");
    Calendar calendar = Calendar.getInstance();
        calendar.setTime(format.parse(date));
    calendar.set(Calendar.HOUR_OF_DAY, 0);
    calendar.set(Calendar.MINUTE, 0);
    calendar.set(Calendar.SECOND, 0);
    calendar.set(Calendar.MILLISECOND, 0);
    return calendar.getTimeInMillis();
}

/**
 * @param date the date in the format "yyyy-MM-dd"
 */
public long getEndOfDayInMillis(String date) throws ParseException {
    // Add one day's time to the beginning of the day.
    // 24 hours * 60 minutes * 60 seconds * 1000 milliseconds = 1 day
    return getStartOfDayInMillis(date) + (24 * 60 * 60 * 1000);
}

Android - 为一天的开始和结束获取Unix时间戳

1 个答案: