假设我们有以下List / IEnumerable
Program : CPE, ECE
旧列表:
Name Assigned_Area Program
Ivan Matala Mathematics CPE
Ivan Matala Mathematics ECE
Jeremy Cruz Science ECE
Ivan Matala Science CPE
NJ Aquino Engineering CPE
MJ Catanaoan Engineering ECE
新列表:
Name Assigned_Area Program
Ivan Matala Mathematics All Programs
Jeremy Cruz Science ECE
Ivan Matala Science CPE
NJ Aquino Engineering CPE
MJ Catanaoan Engineering ECE
基本上,我想要做的是合并“Name”和“Assigned_Area”字段相同的每条记录,如果每条记录都有两个程序(在我们的例子中:'CPE'和'ECE'),那么它应该折叠成一行,其程序现在是“所有程序”。
我们如何使用LINQ做到这一点?
到目前为止我尝试的是以下不完整的代码
var newlist = oldlist.GroupBy(x => x.Assigned_Area);
基本上,我考虑将那些具有相同分配区域的记录分组,但上面的代码是不完整的,因为它只考虑一个字段(我需要考虑2个字段,分别是'Name'和'Assigned_Area'),然后,如果每个分组都有两个计数,如果计数为2,那么我将把它折叠成一个记录,然后用“所有程序”替换该程序。
后续问题但与上述有关..
上述问题适用于非匿名类。基本上,我真正的问题是,我有以下代码
public IEnumerable GetOfficialList(int visitID)
{
db = new PACUCOADB5Entities();
var x = (from a in db.Accreditor_Program
orderby a.Accreditor.Given_Name, a.Accreditor.Middle_Initial, a.Accreditor.Surname, a.Assigned_Area, a.Program.Requested_Program ascending
where a.Program.Visit.VisitID == visitID
select new
{
a.Accreditor.Title,
a.Accreditor.Given_Name,
a.Accreditor.Middle_Initial,
a.Accreditor.Surname,
a.Assigned_Area,
a.Program.Requested_Program
}).ToList();
return x
}
正如你所看到的,'x'是我的列表/ IEnumerable,我试图将相同的概念应用于我正在使用的代码...基本上,我想做同样的事情,但我的尝试是不成功的以下代码
var newx = x.GroupBy(xx => new {xx.Title,xx.Given_Name,xx.Middle_Initial,xx.Surname,xx.Assigned_Area})
.Select(xx => new {xx.Key.Title, xx.Key.Given_Name, xx.Key.Middle_Initial, xx.Key.Surname, xx.Key.Assigned_Area, xx.Count() == 2 ? "All Programs" :x.First(y => y.Title == xx.Key.Title && y.Given_Name == xx.Key.Given_Name && y.Middle_Initial == xx.Key.Middle_Initial && y.Surname == xx.Key.Surname && y.Assigned_Area == xx.Key.Assigned_Area).Requested_Program));
但通过我智能感知错误
我们如何解决?我们如何删除给定代码的重复项。感谢
答案 0 :(得分:3)
oldList.GroupBy(x => new { x.Name, x.AssignedArea })
.Select(g => g.Count() == 1
? new Entity(g.Key.Name, g.Key.AssignedArea, g.Single().Program)
: new Entity(g.Key.Name, g.Key.AssignedArea, "All programs")
);
此处Entity
是您的班级,其中包含Name
,AssignedArea
和Program
字段(代码中没有其名称)。所有这些都可以假设程序计数可以是1或2
答案 1 :(得分:2)
这将有效:
var result = v.GroupBy(x => new { x.Name, x.Assigned_Area})
.Select(x => new EntityName(x.Key.Name,
x.Key.Assigned_Area,
x.Count() == 2 ? "All Programs" :v.First(y => y.Name == x.Key.Name && y.Assigned_Area== x.Key.Assigned_Area).Program) );
答案 2 :(得分:1)
可能有一种更好的方法,但这是我的尝试:
Person[] r = list.GroupBy(p => new { p.Name, p.AssignedArea })
.Select(g => g.ToArray())
.Select(g => g.Length > 1
UpdateProgram(g.First()) :
g.First())
.ToArray();
private static Person UpdateProgram(Person p)
{
p.Program = "All Programs";
return p;
}
但就我个人而言,我会选择分组表达式和常规foreach循环:
foreach (var g in list.GroupBy(p => new { p.Name, p.AssignedArea }))
{
var p = g.First();
if (g.Count() > 1)
{
p.Program = "All Programs";
}
yield return p;
}
答案 3 :(得分:1)
我真的接受了Mark Shevchenko的答案,并考虑了多个具有相同名称的行,AsisgnedArea和Program:
list
.GroupBy(x => new { x.Name, x.Area })
.Select(g =>
g.Select(x=>x.Programs).Distinct().Count() == 1 ?
new Data {Name=g.Key.Name, Area=g.Key.Area, Programs=g.First().Programs} :
new Data {Name=g.Key.Name, Area=g.Key.Area, Programs="All programs"});
你可以用以下方法测试:
public struct Data
{
public string Name;
public string Area;
public String Programs;
}
void Main()
{
var list= new List<Data>()
{
new Data(){ Name="Ivan Matala", Area = "Mathematics", Programs = "CPE" },
new Data(){ Name="Ivan Matala", Area = "Mathematics", Programs = "ECE" },
new Data(){ Name="Jeremy Cruz", Area = "Science", Programs = "ECE" },
new Data(){ Name="Ivan Matala", Area = "Science", Programs = "CPE" },
new Data(){ Name="NJ Aquino", Area = "Engineering", Programs = "CPE" },
new Data(){ Name="MJ Catanaoan", Area = "Engineering", Programs = "ECE" },
new Data(){ Name="MJ Catanaoan", Area = "Science", Programs = "CPE" },
new Data(){ Name="MJ Catanaoan", Area = "Science", Programs = "CPE" }
};
}