我一直在评论我的PHP脚本的部分内容,直到这是我最终的结果。这件事在一分钟内创建了大约200到300个并发连接到SQL ip(从网关检查),我不明白为什么。 不应该关闭SQL连接结束服务器之间的通信吗?
PHP脚本通过JavaScript每秒调用一次,我是网站上唯一的用户。
袜子的PHP实现(取自网络,fclose()
添加,因为我读袜子的方式已关闭)
<?php
$cookie="tD2h6";
$data = $_COOKIE[$cookie];
parse_str($data, $output);
$name = $output['name'];
$pass = $output['pass'];
$con=mysqli_connect("89.33.242.99","global","changeme","global");
$sql = 'SELECT * FROM `users` WHERE `username`=?';
# Prepare statement
$stmt = $con->prepare($sql);
if($stmt === false) {
trigger_error('Wrong SQL: ' . $sql . ' Error: ' . $con->errno . ' ' . $con->error, E_USER_ERROR);
}
# Bind parameters. Types: s = string, i = integer, d = double, b = blob
$stmt->bind_param('s', $name);
# Execute statement
$stmt->execute();
$res = $stmt->get_result();
$row = $res->fetch_assoc();
if($row['password']===$pass && !empty($pass))
{
$hisusername = $name;
$hiscredits = $row['credits'];
$hiseuro = $row['euro'];
}
else
{
$hisusername = "Guest";
$hiscredits = "0";
$hiseuro = "0";
}
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM `users`");
$num_rows = mysqli_num_rows($result);
$result = mysqli_query($con,"SELECT * FROM `users` WHERE admlevel>0");
$num_admrows = mysqli_num_rows($result);
$data = array();
$i=1;
$result = mysqli_query($con,"SELECT * FROM jbchat ORDER BY id DESC LIMIT 7");
while($row = mysqli_fetch_array($result))
{
$data[$i] = $row['string'];
$i=$i+1;
}
for($i=7;$i>0;--$i)
{
$jbchat = $jbchat . $data[$i] . "<br>";
}
unset($data);
$data = array();
$i=1;
$result = mysqli_query($con,"SELECT * FROM frchat ORDER BY id DESC LIMIT 7");
while($row = mysqli_fetch_array($result))
{
$data[$i] = $row['string'];
$i=$i+1;
}
for($i=7;$i>0;--$i)
{
$frchat = $frchat . $data[$i] . "<br>";
}
unset($data);
$data = array();
$i=1;
$result = mysqli_query($con,"SELECT * FROM drchat ORDER BY id DESC LIMIT 7");
while($row = mysqli_fetch_array($result))
{
$data[$i] = $row['string'];
$i=$i+1;
}
for($i=7;$i>0;--$i)
{
$drchat = $drchat . $data[$i] . "<br>";
}
unset($data);
$data = array();
$i=1;
$result = mysqli_query($con,"SELECT * FROM cschat ORDER BY id DESC LIMIT 7");
while($row = mysqli_fetch_array($result))
{
$data[$i] = $row['string'];
$i=$i+1;
}
for($i=7;$i>0;--$i)
{
$cschat = $cschat . $data[$i] . "<br>";
}
$today = getdate();
$date = $today['mday'] . "/" . $today['mon'] . "/" . $today['year'];
if($today['minutes']>9)
$time = $today['hours'] . ":" . $today['minutes'];
else
$time = $today['hours'] . ":0" . $today['minutes'];
$sqlx = 'SELECT * FROM notifications WHERE username=? ORDER BY id DESC LIMIT 5';
# Prepare statement
$stmt = $con->prepare($sqlx);
if($stmt === false) {
trigger_error('Wrong SQL: ' . $sqlx . ' Error: ' . $con->errno . ' ' . $con->error, E_USER_ERROR);
}
# Bind parameters. Types: s = string, i = integer, d = double, b = blob
$stmt->bind_param('s', $name);
$stmt->execute();
$res = $stmt->get_result();
while($row = $res->fetch_assoc())
{
if($row['read']==0)
$nnumber = $nnumber+1;
$notifications = $notifications . "
<li>
<a href=\"#\" onclick=\"invisphp2('http://r4ge.ro/php/readnotif.php?notifid=" . $row['id'] . "')\">
<i class=\"fa fa-warning danger\"></i>" . $row['text'] . "
<br>" . $row['date'] . "
</a>
</li>";
}
$result = mysqli_query($con,"SELECT * FROM chat ORDER BY id DESC LIMIT 30");
$data = array();
$i=1;
while($row = mysqli_fetch_array($result))
{
$data[$i] = $row['name'] . ": " . $row['msg'];
$i=$i+1;
}
for($i=30;$i>0;--$i)
{
$lchat = $lchat . $data[$i] . "<br>";
}
echo json_encode(array(
"registered" => $num_rows,
"admins" => $num_admrows,
"time" => $time,
"date" => $date,
"nnumber" => $nnumber,
"notifications" => $notifications,
"lchat" => $lchat,
"hisusername" => $hisusername,
"hiscredits" => $hiscredits,
"hiseuro" => $hiseuro
));
mysqli_close($con);
?>
编辑:在收听现在删除的评论后,我删除了除第一个以外的每个查询,因此现在正在运行此代码,连接在20-30秒内仍然飙升至150.
<?php
$cookie="tD2h6";
$data = $_COOKIE[$cookie];
parse_str($data, $output);
$name = $output['name'];
$pass = $output['pass'];
$con=mysqli_connect("89.33.242.99","global","changeme","global");
$sql = 'SELECT * FROM `users` WHERE `username`=?';
# Prepare statement
$stmt = $con->prepare($sql);
if($stmt === false) {
trigger_error('Wrong SQL: ' . $sql . ' Error: ' . $con->errno . ' ' . $con->error, E_USER_ERROR);
}
# Bind parameters. Types: s = string, i = integer, d = double, b = blob
$stmt->bind_param('s', $name);
# Execute statement
$stmt->execute();
$res = $stmt->get_result();
$row = $res->fetch_assoc();
if($row['password']===$pass && !empty($pass))
{
$hisusername = $name;
$hiscredits = $row['credits'];
$hiseuro = $row['euro'];
}
else
{
$hisusername = "Guest";
$hiscredits = "0";
$hiseuro = "0";
}
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
echo json_encode(array(
"registered" => $num_rows,
"admins" => $num_admrows,
"time" => $time,
"date" => $date,
"nnumber" => $nnumber,
"notifications" => $notifications,
"lchat" => $lchat,
"hisusername" => $hisusername,
"hiscredits" => $hiscredits,
"hiseuro" => $hiseuro
));
mysqli_close($con);
?>
答案 0 :(得分:0)
我知道这会让我看起来很糟糕。 不幸的是,这个特定的代码没什么不好的。
网站框架中的问题处于更深层次,上面的代码是主页,这让我觉得它是问题的根源。
对于@developerwjk,答案是否定的,结合过程和面向对象的实现对mysqli的功能没有任何影响,它的效果很好。
罪魁祸首:在每个创建连接的PHP结束时缺少mysqli_close()
当文档说在脚本端关闭连接时,不要信任该文档,只是为了安全起见。