Question

我有大量的PFObjects：giantRestaurantArray。我想检查每个数组对象"FoodType"是否包含checkFoodOptionsArray中的任何类型的食物。如果找到食物类型，请将食物类型添加到foundFoodTypes数组。

循环效率低，因为它反复检查数组（即使已找到食物类型）。如何提高搜索效果并跳过已添加的FoodTypes？

 var checkFoodOptionsArray = ["American", "BBQ", "Breakfast", "Buffet", "Burgers", "Cafe", "Wings", "Chinese", "Dessert", "FastFood", "Indian", "Italian", "Japanese", "Korean", "Pizza", "Sandwiches", "Seafood", "Steakhouse", "Thai", "Mexican", "Vietnamese", "Vegan", "OtherEthnic"]

 for items in checkFoodOptionsArray { checkIfFoodTypeOptionAvailable(items) }

 func checkIfFoodTypeOptionAvailable(optionValue: String){
    let isAvailable = contains(giantRestaurantArray as [PFObject]) { (object) -> Bool in
        if let type = object["FoodType"] as? String {
            return type.rangeOfString(optionValue) != nil
        }
        else {
            return false
        }
    }
    if isAvailable == true {
        foundFoodTypes.append(optionValue)
    } else {
        println("No, array does not contain \(optionValue)")
    }
}

Answer 1

您可以只构建Dictionary的{{1}}。建筑可能有点贵，但查找基本上是免费的：

FoodTypes

Answer 2

我认为您只想在找到该项目后立即终止搜索，因此请勿使用contains。

func checkIfFoodTypeOptionAvailable(optionValue: String){
    let isAvailable = false

    for obj in giantRestaurantArray {
        if let object = obj as? PFObject {
            if let type = object["FoodType"] as? String {
                isAvailable = type.rangeOfString(optionValue) != nil
                if isAvailable {
                    break
                }
            }
        }
    }


    if isAvailable == true {
        foundFoodTypes.append(optionValue)
    } else {
        println("No, array does not contain \(optionValue)")
    }
}

在Swift中有效地搜索数组

2 个答案: