我正在制作提交需要上传的数据和图片的表单。我正在用php框架做的所有事情都称为Laravel。我收到错误POST http://xxx/admin/addPost 500 (Internal Server Error)
这是后端的一些错误,我为JSON响应做了控制台日志并得到了这个{"error":{"type":"Symfony\\Component\\Debug\\Exception\\FatalErrorException","message":"Call to a member function move() on a non-object","file":"\/home\/sportcaf\/public_html\/app\/controllers\/admin\/AdminPostsController.php","line":61}}
所以在文件AdminPostsController.php
的第61行,我有这段代码:
$uploadFlag = $image->move('uploads',$imageName);
剩下的代码是:
$date = date("m-d-Y");
$image = Input::file('featured_image'); //Image from posted data
$imageName = $slug."-".$date.".jpg";
$imageThumbName = $slug."-".$date."_thumb.jpg";
$uploadFlag = $image->move('uploads',$imageName); //Here is problem
$img = Image::make('uploads/'.$imageName)->fit(200); //Intervention image package
$img->save('uploads/'.$imageThumbName);
我有表格:
<form id="postForm" action="http://xxx/admin/addPost" method="POST" enctype="multipart/form-data">
Title: <input type='text' name='title'> <br>
Featured image: <input type='file' name='featured_image'> <br>
<section id="editor">
<textarea name='content' id='edit' style="margin-top: 30px;">
</textarea>
</section>
<input type='submit' value='Publish' name='submit'>
</form>
这是我的jQuery(ajax)代码:
$('#postForm').on('submit', function(){
var that = $(this),
url = that.attr('action'),
type = that.attr('method'),
data = {};
that.find('[name]').each(function(index, value){
var that = $(this),
name = that.attr('name'),
value = that.val();
data[name] = value;
});
$.ajax({
url: url,
type: type,
data: data,
success: function(response){
console.log(response);
},
error: function(response){
console.log(response);
}
});
return false;
});