目前,我可以在XML文档中选择属性,因为它们是唯一可识别的,如下所示:
XmlDocument weatherData = new XmlDocument();
weatherData.Load(query);
XmlNode channel = weatherData.SelectSingleNode("rss").SelectSingleNode("channel");
XmlNamespaceManager man = new XmlNamespaceManager(weatherData.NameTable);
man.AddNamespace("yweather", "http://xml.weather.yahoo.com/ns/rss/1.0");
town = channel.SelectSingleNode("yweather:location", man).Attributes["city"].Value;
但是如何从同名节点中选择“text”属性(yweather:forecast)?
<yweather:forecast day="Sat" text="Sunny" code="32"/>
<yweather:forecast day="Sun" text="Partly Cloudy" code="30"/>
<yweather:forecast day="Mon" text="AM Showers" code="39"/>
<yweather:forecast day="Tue" text="Cloudy" code="26"/>
<yweather:forecast day="Wed" text="Cloudy/Wind" code="24"/>
我是否可以使用条件语句来仅选择text
属性等于“Mon”的day
属性?
答案 0 :(得分:1)
这样的事情会起作用:
string xml = "YourXml";
XElement doc = XElement.Parse(xml);
var Result = from a in doc.Descendants("yweather:forecast")
where a.Attribute("day").Value == "Mon"
select a.Attribute("text").Value;
或lambda语法:
var Result = doc.Descendants("yweather:forecast")
.Where(x=> x.Attribute("day").Value == "Mon")
.Select(x=> x.Attribute("text").Value);
您也可以参考此SO post