Question

我有一个表格，其结构如下：

------------------------------
LocationID     | AccountNumber
------------------------------
long-guid-here | 12345
long-guid-here | 54321

要传递到另一个存储过程，我需要XML看起来像这样：

<root> 
    <clientID>12345</clientID>
    <clientID>54321</clientID>
</root>

到目前为止我能做到的最好的就是这样：

<root clientID="10705"/>

我正在使用此SQL语句：

SELECT
    1 as tag,
    null as parent,
    AccountNumber as 'root!1!clientID'
FROM
    Location.LocationMDAccount
WHERE
    locationid = 'long-guid-here'
FOR XML EXPLICIT

到目前为止，我已经查看了the MSDN page上的文档，但是我没有得到预期的结果。

@KG，

你实际上给了我这个输出：

<root>
  <Location.LocationMDAccount>
    <clientId>10705</clientId>
  </Location.LocationMDAccount>
</root>

我现在要坚持使用Chris Leon的FOR XML EXPLICIT。

Answer 1

试

SELECT
    1 AS Tag,
    0 AS Parent,
    AccountNumber AS [Root!1!AccountNumber!element]
FROM
    Location.LocationMDAccount
WHERE
    LocationID = 'long-guid-here'
FOR XML EXPLICIT

Answer 2

试试这个，克里斯：

SELECT
    AccountNumber as [clientId]
FROM
    Location.Location root
WHERE
    LocationId = 'long-guid-here'
FOR
    XML AUTO, ELEMENTS

可怕的抱歉！我混淆了你要求的东西。我更喜欢XML AUTO只是为了便于维护，但我相信其中任何一个都是有效的。我为疏忽道歉; - ）

Answer 3

我明白了：

select
1 as tag,
null as parent,
AccountNumber as 'root!1!clientID!element'
from
Location.LocationMDAccount
where
locationid = 'long-guid-here'
for xml explicit

Answer 4

使用SQL Server 2005（或者可能是2008）我发现XML PATH允许更容易维护SQL而不是XML Explicit（特别是一旦SQL更长）。

在这种情况下：

SELECT AccountNumber as "clientID"
FROM Location.LocationMDAccount
WHERE locationid = 'long-guid-here'
FOR XML PATH (''), Root ('root');

Answer 5

SELECT 1             as tag,
       null          as parent,
       AccountNumber as 'clientID!1!!element'
FROM Location.LocationMDAccount
WHERE locationid = 'long-guid-here'
FOR XML EXPLICIT, root('root')

SQL Server 2005 For XML Explicit - 需要帮助格式化

5 个答案: