我试图通过多个值执行查询。 不幸的是,我无法使用ANY运算符,因为我已经执行了CONTAINS操作。
例:
Obj *foo1 = [Obj objectWithName:@"John" age:42];
Obj *foo2 = [Obj objectWithName:@"Elizabeth" age:21];
Obj *foo3 = [Obj objectWithName:@"Albert" age:17];
Obj *foo4 = [Obj objectWithName:@"Marty" age:54];
NSArray *query = @[@"Joh", @"lizabe", @"arty"];
//此查询应返回foo1
,foo2
和foo4
。
我尝试了类似但不起作用的事情:
[NSPredicate predicateWithFormat:@"(name CONTAINS[cd]) IN %@, query];
有什么建议吗?
答案 0 :(得分:1)
NSMutableArray *filterArray = [NSMutableArray array];
NSArray *query = @[@"Joh", @"lizabe", @"arty"];
for (NSString *string in query)
{
[filterArray addObjectsFromArray:[mainArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"name CONTAINS[cd] IN %@", string]]];
}
此处 mainarray 是包含数组的对象。
或尝试这个..
NSMutableArray *filterArray = [NSMutableArray array];
NSMutableArray *predicateArray = [NSMutableArray array];
NSArray *query = @[@"Joh", @"lizabe", @"arty"];
for (NSString *string in query)
[predicateArray addObject:[NSPredicate predicateWithFormat:@"name CONTAINS[c] %@", string]];
NSPredicate *compoundpred = [NSCompoundPredicate andPredicateWithSubpredicates:predicateArray];
[filterArray addObjectsFromArray:[mainArray filteredArrayUsingPredicate:compoundpred];
我希望这会对你有所帮助......