以下代码是我的应用中的服务器代码:
private int serverPort;
private Thread serverThread = null;
public void networkListen(int port){
serverPort = port;
if (serverThread == null){
Runnable serverRunnable = new ServerRunnable();
serverThread = new Thread(serverRunnable);
serverThread.start();
} else {
}
}
public class ServerRunnable implements Runnable {
public void run(){
try {
//networkConnected = false;
//netMessage = "Listening for Connection";
//networkMessage = new NetworkMessage(networkConnected, netMessage);
//setChanged();
//notifyObservers(networkMessage);
ServerSocket serverSocket = new ServerSocket(serverPort, backlog);
commSocket = serverSocket.accept();
serverSocket.close();
serverSocket = null;
//networkConnected = true;
//netMessage = "Connected: " + commSocket.getInetAddress().getHostAddress() + ":" +
//commSocket.getPort();
//networkMessage = new NetworkMessage(networkConnected, netMessage);
//setChanged();
//notifyObservers(networkMessage);
} catch (IOException e){
//networkConnected = false;
//netMessage = "ServerRunnable Network Unavailable";
//System.out.println(e.getMessage());
//networkMessage = new NetworkMessage(networkConnected, netMessage);
//setChanged();
//notifyObservers(networkMessage);
}
}
}
代码类型的工作,即如果我尝试直接连接两端进行通信和更新。
问题是,如果我想要退出监听,我正在监听连接,那么服务器线程会继续运行并导致问题。
我知道我不应该在线程上使用.stop()所以我想知道解决方案在考虑这个问题时会是什么样子?
编辑:注释掉了不需要的代码。
答案 0 :(得分:12)
从外部线程关闭服务器套接字。根据{{3}}上的文档,阻塞接受将抛出SocketException,您可以关闭线程。
答案 1 :(得分:6)
初始化ServerSocket后,使用setSoTimeout。将accept置于循环中,捕获超时。根据您是否要继续,从循环中断并从run
返回。