Question

// JSONParser.class

公共类JSONParser {

static InputStream is = null;
static JSONObject jobj = null;
static String json = "";
public JSONParser(){

}
public JSONObject makeHttpRequest(String url){
        DefaultHttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(url);
        try {
            HttpResponse httpresponse = httpclient.execute(httppost);
            HttpEntity httpentity = httpresponse.getEntity();
            is = httpentity.getContent();

        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            try {
                while((line = reader.readLine())!=null){
                    sb.append(line+"\n");   

                }
                is.close();
                json = sb.toString();
                try {
                    jobj = new JSONObject(json);
                } catch (JSONException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    return jobj;

}

}

// MainActivity.class

class retrievedata extends AsyncTask<String,String,String>{
    protected String doInBackground(String... arg0) {
        // TODO Auto-generated method stub
        jobj = jsonparser.makeHttpRequest("http://www.mywebsite.com/event/list_event_android.php");

        // check your log for json response
        Log.d("Login attempt", jobj.toString());

        try {
            name = jobj.getString("events");
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return name;
    }
    protected void onPostExecute(String name){
        Toast.makeText(getApplicationContext(), name, Toast.LENGTH_LONG).show();
    }

}

//下面是我当前的输出

{
    "events": [
        {
            "id": "1",
            "name": "Demo Event",
            "descr": "This is a demo",
            "date_d": "12/27/2014",
            "time_t": "",
            "images": "http://www.adagioinfotech.com/event/uploads/event/demo.png",
            "images1": "http://www.adagioinfotech.com/event/uploads/event/demo1.png",
            "location": "Ernakulam",
            "publish": "1"
        },
        {
            "id": "2",
            "name": "Flower Show",
            "descr": "xfvslkdfvsw fvgersdgvel fgvmerlkgjer fgertgkjerltgf dfrgergt",
            "date_d": "12/29/2014",
            "time_t": "",
            "images": "http://www.adagioinfotech.com/event/uploads/event/demo.png",
            "images1": "http://www.adagioinfotech.com/event/uploads/event/demo1.png",
            "location": "Thodupuzha",
            "publish": "1"
        },
        {
            "id": "3",
            "name": "Cultural Event",
            "descr": "sfsdnfkjn sdfrelegkrg fdgvlkgvjmer fdgbelkrek dferlkgelrk dfgerge",
            "date_d": "12/30/2014",
            "time_t": "",
            "images": "http://www.adagioinfotech.com/event/uploads/event/demo.png",
            "images1": "http://www.adagioinfotech.com/event/uploads/event/demo1.png",
            "location": "Idukki",
            "publish": "1"
        }
    ]
}

我想只在名称字段中显示值...是否有任何方法可以这样做???提前谢谢......

Answer 1

events代码是您的JSONArray而不是String。你需要改变这个

name = jobj.getString("events");

到

JSONArray nameArray = jobj.getJSONArray("events");

<强> 编辑：

您可以从events jsonarray获取所有价值。像

for (int i = 0; i < nameArray.length(); ++i) {
 JSONObject arrayObject = nameArray.getJSONObject(i);
 String name = arrayObject.getString("name"); // Same for as other strings.
}

您需要为此{/ 1>为JSONObject创建一个全局变量

  JSONObject arrayObject = nameArray.getJSONObject(i);

或将String name变量设为global，并以onPostExecute()方法访问它。像

  textView.setText(name);

Answer 2

String jsonString = "Here goes your JSON String";

现在，你拥有的第一件事是花括号，所以你需要从String中创建一个JSONObject。

JSONObject jObject = new JSONObject(jSonString);

现在，它包含一个数组（因为＆＃39; []＆＃39;被使用）被称为事件。

JSONArray jArray = jObject.getJSONArray("events");

现在，遍历数组：

for (int i = 0; i < jArray.length(); ++i) {
    JSONObject arrayObject = jArray.getJSONObject(i);
    arrayObject.getString("name");
}

Answer 3

您需要在Json数组中进行迭代。还有更多教程Json Parse

JSON对象到JSONArray

3 个答案: