Question

我需要名字，鉴于phonenumber移动笔记位置在我的csv导出中使用下面的PHP脚本在单独的列中。当前代码将每个记录的所有选定数据导出到一列中。谢谢！

$result = mysql_query('SELECT who as "Name,Given" , phonenumber as "mobile", notes, location FROM `phpbb_phonelist` WHERE `activenumber` = 1'); 
if (!$result) die('Couldn\'t fetch records'); 
$num_fields = mysql_num_fields($result); 
$headers = array(); 
for ($i = 0; $i < $num_fields; $i++) 
{     
   $headers[] = mysql_field_name($result , $i); 
} 
$fp = fopen('php://output', 'w'); 
if ($fp && $result) 
{     
   header('Content-Type: text/csv');
   header('Content-Disposition: attachment; filename="phonelist.csv"');
   header('Pragma: no-cache');    
   header('Expires: 0');
   fputcsv($fp, $headers); 
   while ($row = mysql_fetch_row($result)) 
   {
      fputcsv($fp, array_values($row)); 
   }
die;

Answer 1

使用此代码

// output headers so that the file is downloaded rather than displayed
header('Content-Type: text/csv; charset=utf-8');
header('Content-Disposition: attachment; filename=data.csv');

// create a file pointer connected to the output stream
$output = fopen('php://output', 'w');

// output the column headings
fputcsv($output, array('Column 1', 'Column 2', 'Column 3'));

// fetch the data
mysql_connect('localhost', 'username', 'password');
mysql_select_db('database');
$rows = mysql_query('SELECT field1,field2,field3 FROM table');

// loop over the rows, outputting them
while ($row = mysql_fetch_assoc($rows)) 

   fputcsv($output, $row);

csv php mysql数据导出 - 所有数据都在一列中导出

1 个答案: