我有两个应用程序来监听网络流：另一方面是Server.cs;发送文件Client.cs。但我想从任何文件夹中传输更多文件。例如。我有C：/文件夹，它有3个jpg文件。我的客户必须运行。另外我的server.cs正在获取文件：
Client.cs：
private void btn_send2_Click(object sender, EventArgs e)
{
string[] paths= null;
paths= System.IO.Directory.GetFiles(@"C:\folder" + @"\", "*.jpg", System.IO.SearchOption.AllDirectories);
byte[] Dizi;
TcpClient Gonder = new TcpClient("127.0.0.1", 51124);
FileStream Dosya;
FileInfo Dos;
NetworkStream Akis;
foreach (string path in paths)
{
Dosya = new FileStream(path , FileMode.OpenOrCreate);
Dos = new FileInfo(path );
Dizi = new byte[(int)Dos.Length];
Dosya.Read(Dizi, 0, (int)Dos.Length);
Akis = Gonder.GetStream();
Akis.Write(Dizi, 0, (int)Dosya.Length);
Gonder.Close();
Akis.Flush();
Dosya.Close();
}
}我也有Server.cs
void Dinle()
{
TcpListener server = null;
try
{
Int32 port = 51124;
IPAddress localAddr = IPAddress.Parse("127.0.0.1");
server = new TcpListener(localAddr, port);
server.Start();
Byte[] bytes = new Byte[1024 * 250000];
// string ReceivedPath = "C:/recieved";
while (true)
{
MessageBox.Show("Waiting for a connection... ");
TcpClient client = server.AcceptTcpClient();
MessageBox.Show("Connected!");
NetworkStream stream = client.GetStream();
if (stream.CanRead)
{
saveFileDialog1.ShowDialog();
// burası degişecek
string pathfolder = saveFileDialog1.FileName;
StreamWriter yaz = new StreamWriter(pathfolder);
string satir;
StreamReader oku = new StreamReader(stream);
while ((satir = oku.ReadLine()) != null)
{
satir = satir + (char)13 + (char)10;
yaz.WriteLine(satir);
}
oku.Close();
yaz.Close();
client.Close();
}
}
}
catch (SocketException e)
{
Console.WriteLine("SocketException: {0}", e);
}
finally
{
// Stop listening for new clients.
server.Stop();
}
Console.WriteLine("\nHit enter to continue...");
Console.Read();
}请查看Client.cs：icollected“c：\ folder”
中的所有文件 paths= System.IO.Directory.GetFiles(@"C:\folder" + @"\", "*.jpg", System.IO.SearchOption.AllDirectories);我的Server.cs如何从流中获取所有文件？
答案 0 :(得分：0)
这不是一种典型的做事方式。
通常，您会在单个流中编写单个文件，并为多个文件重复此过程。您可能会以这种方式冒着数据损坏的风险，因为您必须在流中放置某种标记才能知道将其拆分的位置。
答案 1 :(得分：0)
最简单的方法是使用多个套接字，一个用于命令，一个（或多个）用于发送文件。
以下代码尚未经过测试，只是写下来表明我的意思。它是多线程的，可以从同一个客户端接收多个文件，只需在客户端多次调用sendfiles即可。
如果您决定完成代码，可能需要添加错误/异常处理。
<强> Server.cs
using System;
using System.IO;
using System.Net;
using System.Net.Sockets;
using System.Text;
namespace Test2
{
public class Server
{
private readonly TcpListener _listener = new TcpListener(1234);
public void Start()
{
_listener.BeginAcceptTcpClient(OnClient, null);
}
private void OnClient(IAsyncResult ar)
{
// End async accept and start wait for a new connection again
TcpClient client = _listener.EndAcceptTcpClient(ar);
_listener.BeginAcceptTcpClient(OnClient, null);
// Let's start receiving files from the accepted client.
var context = new Context {Client = client, Buffer = new byte[8196]};
client.GetStream().BeginRead(context.Buffer, 0, context.Buffer.Length, OnReceive, context);
}
/// <summary>
/// Got some stuff from a client
/// </summary>
/// <param name="ar"></param>
private void OnReceive(IAsyncResult ar)
{
// got a file command
var context = (Context) ar.AsyncState;
int bytesRead = context.Client.GetStream().EndRead(ar);
string cmd = Encoding.UTF8.GetString(context.Buffer, 0, bytesRead);
string[] parts = cmd.Split(';');
string command = parts[0];
// want to send another file
if (command == "sendfile")
{
// context info for receiving files
var client = new FileClient();
client.FileName = parts[1];
client.Size = long.Parse(parts[2]);
client.FileStream = new FileStream("C:\\" + client.FileName, FileMode.CreateNew, FileAccess.Write);
// startup listener where we are going to receive the file.
var listener = new TcpListener(IPAddress.Any, 0); // get a kernelassigned number
client.Listener = listener;
listener.Start();
listener.BeginAcceptTcpClient(OnFileSocket, client);
// send reply
var ep = (IPEndPoint) listener.LocalEndpoint;
byte[] reply = Encoding.UTF8.GetBytes(ep.Port.ToString());
context.Client.GetStream().Write(reply, 0, reply.Length);
}
}
// Receiving the actual files.
private void OnFileSocket(IAsyncResult ar)
{
var client = (FileClient) ar.AsyncState;
client.Socket = client.Listener.EndAcceptTcpClient(ar);
var buffer = new byte[8192];
client.Buffer = buffer;
client.Socket.GetStream().BeginRead(buffer, 0, buffer.Length, OnReceiveFile, client);
}
private void OnReceiveFile(IAsyncResult ar)
{
var client = (FileClient) ar.AsyncState;
int bytesRead = client.Socket.GetStream().EndRead(ar);
client.Received += bytesRead;
client.FileStream.Write(client.Buffer, 0, bytesRead);
// recieved complete file, disconnect and exit.
if (client.Received == client.Size)
{
client.FileStream.Close();
client.Socket.Close();
return;
}
client.Socket.GetStream().BeginRead(client.Buffer, 0, client.Buffer.Length, OnReceiveFile, client);
}
#region Nested type: Context
private class Context
{
public byte[] Buffer;
public TcpClient Client;
}
#endregion
#region Nested type: FileClient
private class FileClient
{
public byte[] Buffer;
public string FileName;
public FileStream FileStream;
public TcpListener Listener;
public long Received;
public long Size;
public TcpClient Socket;
}
#endregion
}
}
<强> Client.cs
using System;
using System.IO;
using System.Net;
using System.Net.Sockets;
using System.Text;
namespace Test2
{
internal class Client
{
private readonly IPAddress _server;
private readonly TcpClient _tcpClient = new TcpClient();
public Client(IPAddress server)
{
_server = server;
_tcpClient = new TcpClient();
}
public void Connect()
{
_tcpClient.Connect(new IPEndPoint(_server, 1234));
}
// asks server on which port the file should be sent.
private int RequestPort(string fileName, long length)
{
// lock tpcClient for each request, so we dont mix up the responses.
lock (_tcpClient)
{
// send request
byte[] bytes = Encoding.UTF8.GetBytes("sendfile;" + fileName + ";" + length);
_tcpClient.GetStream().Write(bytes, 0, bytes.Length);
// get reply
var buffer = new byte[1024];
int bytesRead = _tcpClient.GetStream().Read(buffer, 0, buffer.Length);
string reply = Encoding.UTF8.GetString(buffer, 0, bytesRead);
// error message or port?
int port;
if (!int.TryParse(reply, out port))
throw new InvalidOperationException("Server sent an error:" + reply);
return port;
}
}
public void SendFiles(string[] fileNames)
{
// Use a buffer to not preserve memory (instead of reading whole file into memory)
var buffer = new byte[8192];
foreach (string fileName in fileNames)
{
using (var fileStream = new FileStream(fileName, FileMode.Open, FileAccess.Read, FileShare.ReadWrite))
{
// Send on commandchannel that we want to send a file.
int filePort = RequestPort(Path.GetFileName(fileName), fileStream.Length);
var client = new TcpClient(new IPEndPoint(_server, filePort));
NetworkStream stream = client.GetStream();
// repeat until there are no more bytes to read.
int bytesRead = fileStream.Read(buffer, 0, buffer.Length);
while (bytesRead > 0)
{
stream.Write(buffer, 0, bytesRead);
bytesRead = fileStream.Read(buffer, 0, buffer.Length);
}
stream.Close();
client.Close();
}
}
}
}
}