我很确定这个问题有一个简单的解决方案,但我还没能解决它。
情景:
1)我有一个JTable链接到一个基于LinkedHashMap的模型(例如)10个元素。
2)外部事件几乎同时删除前两个元素,因此:
2.1)模型删除元素#0,并抛出一个事件,如"行链接到元素#0,行#0,已更改"。
2.2)在JTable有时间修改之前,第二个元素在模型上被删除并且启动的事件是相同的,因为第二个元素现在是第一个元素。
3)JTable处理两个事件"第0行已被删除"。
我认为这就是为什么我得到一个" NULL错误"如下所示:
Exception in thread "AWT-EventQueue-0" java.lang.NullPointerException
at paneles.panel_positions.Elements_Manager.getValueAt(Elements_Manager.java:388)
at paneles.panel_positions.Elements_Manager$1Dates_Renderer.getTableCellRendererComponent(Positions_Manager.java:891)
at javax.swing.JTable.prepareRenderer(JTable.java:5736)
at javax.swing.plaf.basic.BasicTableUI.paintCell(BasicTableUI.java:2114)
at javax.swing.plaf.basic.BasicTableUI.paintCells(BasicTableUI.java:2016)
at javax.swing.plaf.basic.BasicTableUI.paint(BasicTableUI.java:1812)
at javax.swing.plaf.ComponentUI.update(ComponentUI.java:161)
at javax.swing.JComponent.paintComponent(JComponent.java:778)
at javax.swing.JComponent.paint(JComponent.java:1054)
at javax.swing.JComponent.paintChildren(JComponent.java:887)
at javax.swing.JComponent.paint(JComponent.java:1063)
at javax.swing.JViewport.paint(JViewport.java:731)
at javax.swing.JComponent.paintChildren(JComponent.java:887)
at javax.swing.JComponent.paint(JComponent.java:1063)
at javax.swing.JComponent.paintToOffscreen(JComponent.java:5230)
at javax.swing.BufferStrategyPaintManager.paint(BufferStrategyPaintManager.java:295)
at javax.swing.RepaintManager.paint(RepaintManager.java:1249)
at javax.swing.JComponent._paintImmediately(JComponent.java:5178)
at javax.swing.JComponent.paintImmediately(JComponent.java:4989)
at javax.swing.RepaintManager$3.run(RepaintManager.java:808)
at javax.swing.RepaintManager$3.run(RepaintManager.java:796)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:76)
at javax.swing.RepaintManager.paintDirtyRegions(RepaintManager.java:796)
at javax.swing.RepaintManager.paintDirtyRegions(RepaintManager.java:769)
at javax.swing.RepaintManager.prePaintDirtyRegions(RepaintManager.java:718)
at javax.swing.RepaintManager.access$1100(RepaintManager.java:62)
at javax.swing.RepaintManager$ProcessingRunnable.run(RepaintManager.java:1677)
at java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:312)
at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:733)
at java.awt.EventQueue.access$200(EventQueue.java:103)
at java.awt.EventQueue$3.run(EventQueue.java:694)
at java.awt.EventQueue$3.run(EventQueue.java:692)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:76)
at java.awt.EventQueue.dispatchEvent(EventQueue.java:703)
at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:242)
at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:161)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:150)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:146)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:138)
at java.awt.EventDispatchThread.run(EventDispatchThread.java:91)
我一直在思考任何类型的同步机制,因此第二次删除不能执行,直到第一次删除完成并在JTable上执行事件,但我无法理解它可能是正确的做法。
这是在一个真实的时间事件处理应用程序上发生的,因此强制事件源以这种方式等待似乎不是一个好的解决方案,但我无法弄清楚它是否正确这样做的方式。有什么想法吗?
提前致谢。
编辑:
启动删除的另一个线程上的方法:
public void delete_all_elements() {
cloned_model = mainobject.getCloned_model();
for (Element pos_aux : cloned_model.values()) {
notify_pos_to_be_deleted(pos_aux);
}
}
在线程上执行的代码,它接收消息队列上的上一条消息:
...
model.rmv(row_index);
TableModelEvent event = new TableModelEvent (this, row_index, total_rows-1, TableModelEvent.ALL_COLUMNS, TableModelEvent.DELETE);
notify_suscriptors(event);
...
notify_suscriptors代码:
...
((TableModelListener)listeners.get(i)).tableChanged(event);
...
答案 0 :(得分:2)
您必须更新event dispatch thread上的Table Model
。使用EventQueue.invokeLater()
,如相关的example。
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
// remove row
}
});