如何从listView开始播放歌曲?

时间:2015-01-17 10:19:12

标签: c# xaml windows-phone-8

我在设备上创建了一系列歌曲。

对于每个项目,在我的ListView中显示艺术家姓名和歌曲名称。我希望当选择一首歌时,开始播放,我该怎么办?

StorageFolder musicLibrary = KnownFolders.MusicLibrary;
IReadOnlyList<StorageFile> musica = await musicLibrary.GetFilesAsync();

if (musica != null)
{
    List<Testo> song = new List<Testo>();
    {           
        foreach (StorageFile storage in musica)
        {
            MusicProperties musicProp = await storage.Properties.GetMusicPropertiesAsync();

            song.Add(new Testo
            {
                NomeArtista = musicProp.Artist,
                NomeCanzone = musicProp.Title,
                Anno = (int)musicProp.Year,

            });                            
        }
    }
}

private async void TestiCanzone_ItemClick(object sender, ItemClickEventArgs e)
{
    Testo NuovoTesto = e.ClickedItem as Testo;
}

我还创建了一个MediaElement

<MediaElement x:Name="AudioPlay" Source="" AutoPlay="True"/>

1 个答案:

答案 0 :(得分:0)

您需要将listview的SelectedValue绑定到viewmodel上的某个属性:

 <ListView SelectedItem="{Binding SelectedAudio, Mode=TwoWay}"/>

在您的viewmodel上,您需要处理更改属性:

public string SelectedCustomMusic
    {
        get
        {
            return this.selectedCustomMusic;
        }
        set
        {
            if (value != null)
            {
                this.selectedCustomMusic = value;
                this.MusicSource = this.selectedCustomMusic;
                base.OnPropertyChanged();
            }
        }
    }

然后将this.MusicSource绑定到Source的{​​{1}}。