Question

我试着自己写这个，但我失败了。现在我有一个脚本检查我的游戏中的分数。我检查每100分并根据分数改变一个变量，但我做错了而且单调乏味：

if(gameController.speed == 1) {

    if(score >= 200) {
        squishyController.gravity = -25;
    }

    if(score >= 300) {
        squishyController.gravity = -50;
    }

    if(score >= 400) {
        squishyController.gravity = -75;
    }

    if(score >= 500) {
        squishyController.gravity = -100;
        gamePause = true;
        // Spawn First Boss
    }

    if(score >= 600) {
        squishyController.gravity = -125;
    }

    if(score >= 700) {
        squishyController.gravity = -150;
    }
}

你明白了。我想用word形式做的是：

每100分
- 将重力改变-25
- 如果积分是500,1000等
- 产生老板

简而言之。这就是我认为的样子，但不要杀了我。

for (var i = 0; i += pointValue) {

// Check if points are being added then add to score depending on point value
if(getPoints == true) {
  i++;
}


// For every 100 points change the gravity value
if(i >= incrementsOf100) {
  gravity = gravity -= 25;
}

// For every 500 points, spawn a boss more difficult than the last

if(i = incrementsOf500) {
  bossDifficulty = bossDifficulty += 100; // Just adding this because I will add more hitpoints to boss.
  spawnBoss = true;
}

}

Answer 1

如何使用modus运算符查找除以100的余数，然后将得分除以该余数以得到您需要更改重力的次数

var score = 550;
var extra = score % 100;
var gravityTimes = (score - extra) / 100;

gravity = gravity -= (25 * gravityTimes);

JS功能每100分

1 个答案: