Question

您好我是XSLT新手我想要转换学生名称映射的Xml数据集，其中有一个学生名称和卷号的数据集。 classwise。

我想使用xslt，但我不想将所有标签添加到要映射的列名标签中，并按原样放置其他列。

这是输入和输出数据集示例。 xml是来自c＃代码的普通数据集.writexml。

表1：

RollNo    Sub1  Sub2 Sub3 Sub4
1         65    89   67   34
2         67    86   67   76
3         86    67   78   45
4         56    56   87   56
5         76    56   56   78

表2

Name      Sub1  Sub2 Sub3 Sub4
Aman      65    89   67   34
Ankit     67    86   67   76
Om        86    67   78   45
Narendra  56    56   87   56
Faisal    76    56   56   78

这是用于转换的Xml

映射XML

<?xml version="1.0" standalone="yes"?>
<School>
    <Class Name="Class1">
        <StudentData Name="Aman" RollNo="1"  />   
        <StudentData Name="Ankit" RollNo="2"  />   
        <StudentData Name="Om" RollNo="3"  />   
        <StudentData Name="Narendra" RollNo="4"  />   
        <StudentData Name="Faisal" RollNo="5"  />    
    </Class>
    <Class Name="Class2">
        <StudentData Name="Abhinav" RollNo="1"  />   
        <StudentData Name="Abhishek" RollNo="2"  />   
        <StudentData Name="Ishaan" RollNo="3"  />   
        <StudentData Name="Mayank" RollNo="4"  />   
        <StudentData Name="Bhavana" RollNo="5"  />    
    </Class>
</School>

到目前为止创建的XSLT

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs"
             xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:user="http://www.contoso.com">
  <xsl:output method="xml" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/>

  <xsl:template match="/">
    <DocumentElement>
      <xsl:for-each select="//Comparision">
        <xsl:if test ="number(COL7)">
      <PositionMaster>

                    <xsl:variable name="RollNo" select="normalize-space(COL1)"/>
                    <xsl:variable name="Name">
                        <xsl:value-of select="document('../../../MappingFiles/Mapping.xml')/School/PB[@Name='Class1']/TagData[@RollNo=$RollNo]/@Name"/>
                    </xsl:variable>
                    <Name>
                        <xsl:choose>
                            <xsl:when test="$Name!=''">
                                <xsl:value-of select="$Name"/>
                            </xsl:when>
                            <xsl:otherwise>
                                <xsl:value-of select="$Name"/>
                            </xsl:otherwise>
                        </xsl:choose>
                    </Name>
          </PositionMaster>
        </xsl:if >
      </xsl:for-each>
    </DocumentElement>
  </xsl:template>
</xsl:stylesheet>

由于阿曼

Answer 1

举个例子，给出以下输入XML ：

<Table>
    <Student>
        <RollNo>1</RollNo>
        <Sub1>11</Sub1>
        <Sub2>12</Sub2>
        <Sub3>13</Sub3>
    </Student>
    <Student>
        <RollNo>2</RollNo>
        <Sub1>21</Sub1>
        <Sub2>22</Sub2>
        <Sub3>23</Sub3>
    </Student>
    <Student>
        <RollNo>3</RollNo>
        <Sub1>31</Sub1>
        <Sub2>32</Sub2>
        <Sub3>33</Sub3>
    </Student>
    <Student>
        <RollNo>4</RollNo>
        <Sub1>41</Sub1>
        <Sub2>42</Sub2>
        <Sub3>43</Sub3>
    </Student>
    <Student>
        <RollNo>5</RollNo>
        <Sub1>51</Sub1>
        <Sub2>52</Sub2>
        <Sub3>53</Sub3>
    </Student>
</Table>

和名为“Mapping.xml”的外部文件：

<?xml version="1.0" standalone="yes"?>
<School>
    <Class Name="Class1">
        <StudentData Name="Aman" RollNo="1"  />   
        <StudentData Name="Ankit" RollNo="2"  />   
        <StudentData Name="Om" RollNo="3"  />   
        <StudentData Name="Narendra" RollNo="4"  />   
        <StudentData Name="Faisal" RollNo="5"  />    
    </Class>
    <Class Name="Class2">
        <StudentData Name="Abhinav" RollNo="1"  />   
        <StudentData Name="Abhishek" RollNo="2"  />   
        <StudentData Name="Ishaan" RollNo="3"  />   
        <StudentData Name="Mayank" RollNo="4"  />   
        <StudentData Name="Bhavana" RollNo="5"  />    
    </Class>
</School>

以下样式表：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:param name="class">Class2</xsl:param>

<xsl:key name="student" match="StudentData" use="concat(@RollNo, '|' , ../@Name)" />

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="RollNo">
    <Name>
        <xsl:variable name="RollNo" select="." />
        <!-- switch context to the other document in order to use key -->
        <xsl:for-each select="document('Mapping.xml')">
            <xsl:value-of select="key('student', concat($RollNo, '|' , $class))/@Name" />
        </xsl:for-each>
    </Name>
</xsl:template>

</xsl:stylesheet>

将返回：

<?xml version="1.0" encoding="UTF-8"?>
<Table>
   <Student>
      <Name>Abhinav</Name>
      <Sub1>11</Sub1>
      <Sub2>12</Sub2>
      <Sub3>13</Sub3>
   </Student>
   <Student>
      <Name>Abhishek</Name>
      <Sub1>21</Sub1>
      <Sub2>22</Sub2>
      <Sub3>23</Sub3>
   </Student>
   <Student>
      <Name>Ishaan</Name>
      <Sub1>31</Sub1>
      <Sub2>32</Sub2>
      <Sub3>33</Sub3>
   </Student>
   <Student>
      <Name>Mayank</Name>
      <Sub1>41</Sub1>
      <Sub2>42</Sub2>
      <Sub3>43</Sub3>
   </Student>
   <Student>
      <Name>Bhavana</Name>
      <Sub1>51</Sub1>
      <Sub2>52</Sub2>
      <Sub3>53</Sub3>
   </Student>
</Table>

XML数据集转换

1 个答案: