Question

我想创建一个查询，我只查找具有最早和最新registration_date的成员的详细信息。到目前为止我已经

了

SELECT member_id, UPPER(name), registration_date 
from db.member WHERE registration_date >=
'2012-01-01'

我不确定如何找到最小/最大但我只是在设定日期2012-01-01测试它

因此查询应该只返回两个结果 - 最小/最大

提前谢谢

Answer 1

您可以在子查询中获得min，max个日期，然后就可以获得结果。

select member_id, upper(name), registration_date
from db.member
cross join (
       select min(registration_date) as minDate, max(registration_date) as maxDate
       from db.member ) t
where registration_date in ( t.minDate, t.maxDate)

或者您可以使用in和union

执行此操作

select member_id, upper(name), registration_date
from db.member
where registration_date in  (
       select min(registration_date) 
       from db.member
       union 
       select max(registration_date) as maxDate
       from db.member )

Answer 2

从表中选择min（日期列），max（日期列）;

Answer 3

类似下面这样的东西，虽然有点子查询，可能会让你最接近你需要的东西。根据SQL（Oracle，SQLServer，MySQL等）的风格，您可以限制IN结果集子查询中member_id选择的子查询。

select member_id, Upper(name) AS name, registration_date 
from db.member 
where member_id in
(
    select Min(member_id) 
    from db.member
    where registration_date =
    (
        select Min(registration_date)
        from db.member
    )
    union all
    select Max(member_id) 
    from db.member
    where registration_date = 
    (
        select Max(registration_date)
        from db.member
    )
)
order by registration_date desc;

查找最小和最大日期SQL

3 个答案: