我正在尝试使用1个select语句从2个表中检索数据。
测试一次失败
$sql = "SELECT banned FROM users WHERE id =:id UNION SELECT first_name, last_name,
mobile_phone,email, city, address, postal_code, user_type,
active FROM personal WHERE id =:id";
我从这次尝试中了解到,您无法选择不同数量的列,甚至可以使其工作。
尝试两次失败
$sql = "SELECT users.banned, personal.first_name, personal.last_name, personal.mobile_phone,
personal.email, personal.city, personal.address, personal.postal_code, personal.user_type,
personal.active FROM users WHERE users.id =:id INNER JOIN personal WHERE personal.id =:id";
得到了这个:SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN personal WHERE personal.id ='21'
尝试按别名选择失败
上次尝试失败
$sql = "SELECT banned, first_name, last_name, mobile_phone, email, city, address, postal_code, user_type, active FROM users WHERE users.id =:id INNER JOIN personal WHERE personal.id =:id";
缺少想法或尝试做错事。
答案 0 :(得分:1)
您的语法和逻辑不正确:
SELECT u.banned
, p.first_name
, p.last_name
, p.mobile_phone
, p.email
, p.city
, p.address
, p.postal_code
, p.user_type
, p.active
FROM users u JOIN personal p ON u.id = p.id
WHERE u.id =:id
一些提示:
UNION
或UNION ALL
时,您应该记住,所涉及的所有SELECT
应该具有相同数量的字段。WHERE
始终追踪FROM
和JOIN
ON
条款。