大家好，新年快乐
我有JSON类，我在其中检索从数据库检索的一些数据。此JSON文件的格式为
{"people":[{"id":"15","first_name":"Theo","last_name":"Tziomakas","bio":"Hello from
Theo!!!","created":"2015-01-11 21:48:51"},
{"id":"16","first_name":"Jim","last_name":"Chytas","bio":"Hello from Chytas","created":"2015-01-11
21:53:42"}]}.
想法是在列表视图中检索“first_name”和“second_name”。 “生物”应出现在另一项活动中，但我不知道该怎么做：（。
这是我的代码。
public class MainActivity extends ActionBarActivity {
ListView list;
TextView fname;
TextView lname;
ArrayList<HashMap<String, String>> oslist = new ArrayList<HashMap<String, String>>();
//URL to get JSON Array
private static String url = "http://xxxxxxx/tutorials/index.php";
//JSON Node Names
private static final String TAG_OS = "people";
private static final String TAG_FIRST_NAME = "first_name";
private static final String TAG_SECOND_NAME = "last_name";
//private static final String TAG_BIO = "bio";
JSONArray android = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
oslist = new ArrayList<HashMap<String, String>>();
new JSONParse().execute();
}
private class JSONParse extends AsyncTask<String, String, JSONObject> {
private ProgressDialog pDialog;
@Override
protected void onPreExecute() {
super.onPreExecute();
fname = (TextView)findViewById(R.id.first_name);
lname = (TextView)findViewById(R.id.last_name);
//abio = (TextView)findViewById(R.id.bio);
pDialog = new ProgressDialog(MainActivity.this);
pDialog.setMessage("Getting Data ...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
@Override
protected JSONObject doInBackground(String... args) {
JSONParser jParser = new JSONParser();
// Getting JSON from URL
JSONObject json = jParser.getJSONFromUrl(url);
return json;
}
@Override
protected void onPostExecute(JSONObject json) {
pDialog.dismiss();
try {
// Getting JSON Array from URL
android = json.getJSONArray(TAG_OS);
for(int i = 0; i < android.length(); i++){
JSONObject c = android.getJSONObject(i);
// Storing JSON item in a Variable
String first_name = c.getString(TAG_FIRST_NAME);
String last_name = c.getString(TAG_SECOND_NAME);
//String bio = c.getString(TAG_BIO);
// Adding value HashMap key => value
HashMap<String, String> map = new HashMap<String, String>();
map.put(TAG_FIRST_NAME, first_name);
map.put(TAG_SECOND_NAME, last_name);
//map.put(TAG_BIO, bio);
oslist.add(map);
list=(ListView)findViewById(R.id.list);
ListAdapter adapter = new SimpleAdapter(MainActivity.this, oslist,
R.layout.list_v,
new String[] { TAG_FIRST_NAME,TAG_SECOND_NAME }, new int[] {
R.id.first_name,R.id.last_name});
list.setAdapter(adapter);
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
String bio = ((TextView) view.findViewById(R.id.bio))
.getText().toString();
switch (position) {
case 0:
Intent i = new Intent(MainActivity.this, SingleActivity.class);
i.putExtra("bio", bio);
startActivity(i);
break;
}
}
});
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}
}
最后我有了SecondActivity类，但是当我点击第一行列表时没有显示任何内容。
public class SingleActivity extends ActionBarActivity {
TextView text;
JSONArray android = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_single);
text = (TextView)findViewById(R.id.text);
String bio = getIntent().getStringExtra("bio");
try {
JSONObject profileJSON = new JSONObject(bio);
android = profileJSON.getJSONArray(bio);
text.setText(""+android);
} catch (JSONException e) {
e.printStackTrace();
}
}
}
谢谢。
编辑：我遇到的问题是固定的。现在我想做点别的事。让我们假设我们通过更改“first_name”，“last_name”和最终生物来更新现有行中的数据。在phpmyadmin工具中很容易完成。问题是更新的行没有显示在列表视图中。我必须重新安装应用程序以便查看它。有任何想法吗？答案 0 :(得分：1)
试试这个，
用此
替换onPostExecute protected void onPostExecute(JSONObject json) {
pDialog.dismiss();
try {
list=(ListView)findViewById(R.id.list);
// Getting JSON Array from URL
android = json.getJSONArray(TAG_OS);
for(int i = 0; i < android.length(); i++){
JSONObject c = android.getJSONObject(i);
// Storing JSON item in a Variable
String first_name = c.getString(TAG_FIRST_NAME);
String last_name = c.getString(TAG_SECOND_NAME);
//String bio = c.getString(TAG_BIO);
// Adding value HashMap key => value
HashMap<String, String> map = new HashMap<String, String>();
map.put(TAG_FIRST_NAME, first_name);
map.put(TAG_SECOND_NAME, last_name);
map.put(TAG_BIO, bio);
oslist.add(map);
}
ListAdapter adapter = new SimpleAdapter(MainActivity.this, oslist,
R.layout.list_v,
new String[] { TAG_FIRST_NAME,TAG_SECOND_NAME }, new int[] {
R.id.first_name,R.id.last_name});
list.setAdapter(adapter);
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
String bio =oslist.get(position).get(TAG_BIO);
// switch (position) {
// case 0:
Intent i = new Intent(MainActivity.this, SingleActivity.class);
i.putExtra("bio", bio);
startActivity(i);
break;
//}
}
});
} catch (JSONException e) {
e.printStackTrace();
}
}
和SingleActivity
text = (TextView)findViewById(R.id.text);
String bio = getIntent().getStringExtra("bio");
text.setText(bio );
答案 1 :(得分：0)
注意你对意图的投入。
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
String bio = ((TextView) view.findViewById(R.id.bio))
.getText().toString();
switch (position) {
case 0:
Intent i = new Intent(MainActivity.this, SingleActivity.class);
i.putExtra("bio", bio);
startActivity(i);
break;
}
}
请注意，您从文本视图中获取文本并将其添加到and intent。
当你进行检索时，就像使用json对象一样使用它。 如果你想要生物字符串，你可以把它放在一个变量中，然后把它发送到只有字符串的意图。
例如
ListAdapter adapter = new SimpleAdapter(MainActivity.this, oslist,
R.layout.list_v,
new String[] { TAG_FIRST_NAME,TAG_SECOND_NAME }, new int[] {
R.id.first_name,R.id.last_name});
list.setAdapter(adapter);
String bio = c.getString("bio");
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
switch (position) {
case 0:
Intent i = new Intent(MainActivity.this, SingleActivity.class);
i.putExtra("bio", bio);
startActivity(i);
break;
}
}
});
检索时，使用
更容易实现public class SingleActivity extends ActionBarActivity {
TextView text;
JSONArray android = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_single);
text = (TextView)findViewById(R.id.text);
String bio = getIntent().getStringExtra("bio");
text.settext(bio)
}
}
现在这些例子中存在一些错误，因为我的计算机上没有安装java或android sdk