您好我希望得到一些帮助我对python很新,我想要一些关于如何设置条件的建议,以便在我的数据中遇到-inf然后程序将循环到下一次迭代
import numpy as np
import math
import matplotlib.pylab as plt
import pandas as pd
from scipy.interpolate import interp1d
from scipy.signal import butter, filtfilt
from scipy import interpolate
Ic = 400
lower_Ig = 720 #the lower limit of the generator current Ig
Upper_Ig = 1040 #Upper limit
Ix=range(-60,61,1)
for j in range(40, 80, 10):
Var=(40000* j)/ 10000
#print Var
for c in range(lower_Ig, Upper_Ig+1, 40):
#print c
Names =['Vg','V3', 'V4']
Data = pd.read_csv('/Documents/JTL_'+str(Var)+'/Ig='+str(c)+'/Grey_Zone.csv', names=Names)
Vg = Data['Vg']
V3 = Data['V3']
V4 = Data ['V4']
Prf = V4 / Vg
#print Prf
C = 0.802
freq = 100
b, a = butter(2, (5/C)/(freq/2), btype = 'low')
yg = filtfilt(b, a, Vg) # filter with phase shift correction
y4 = filtfilt(b, a, V4) # filter with phase shift correction
SW = y4 / yg
if SW == np.nan: #I need a condition here that if -inf is encountered then the programme should loop to next c value in for loop
continue
f = interp1d( SW, Ix )
print f(0.25), f(0.5), f(0.75)
print f(0.75)-f(0.25)
我尝试使用不同的numpy函数,但我总是得到相同的错误
The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
我不认为我可以使用any()
或all()
,因为那只包含所有数据,我想忽略-inf。非常感谢任何帮助
答案 0 :(得分:1)
假设我们在循环的一次迭代中有SW
,如下所示:
>>> import numpy as np
>>> SW = [np.inf, -np.inf, np.nan, 0, 1]
>>> np.isfinite(SW)
[False, False, False, True, True]
>>> all(np.isfinite(SW))
False # since one or more in the list is False
如果您想跳过SW
的任何nan, inf, -inf
,您可以使用
if not all(np.isfinite(SW)):
continue
如果nan
不是问题,只有-inf
则可以使用
if any(np.isneginf(SW)):
continue
如果SW
的任何元素为-inf
请注意,您无法使用==
与np.nan
>>> x = np.nan
>>> x == np.nan
False
而是使用isnan
>>> np.isnan(x)
True
答案 1 :(得分:0)
您可以filter
删除不需要的元素(例如newlist=filter(lambda n: not numpy.isneginf(n), list_of_numbers)
),或者只使用numpy.nan_to_num(...)
转换为正确的数字列表。