Question

是否可以编写一个生成类型提供程序，它提供与以下F＃代码等效的类型？

[<ProvidedTypeFlag("myTypeA")>]
type A(x:int) =
    inherit ValueType(x)
    member __.X = x+1

[<ProvidedTypeFlag("myTypeB")>]
type B(value:ValueType) =
    member __.Raw = value
    member __.toA = A(value.X)

    interface IComparable with
        member this.CompareTo obj =
            match obj with
            | :? B as other -> this.Raw.X.CompareTo (other.Raw.X)
            | _             -> invalidArg "obj" "not a B"

[<ProvidedTypeFlag("myTypeC")>]
type C() =
    static member Process(a:A) =
        seq {
            for x in [1..a.X] do
                yield B(ValueType(x))
        } |> Set.ofSeq

假设我在同一个程序集中有以下类型

// Value type that hold some data from 3rd party system
type ValueType (x:int) =
    member __.X = x

// Custom attribute that I want to have on provided types
[<AttributeUsage(AttributeTargets.Class, AllowMultiple=false)>]
type ProvidedTypeFlagAttribute(originName:string) =
   inherit System.Attribute()
   member __.OriginName = originName

如果可能，请使用ProvidedTypes.fs

提供如何操作的示例

Answer 1

看着这看起来你需要几件小件。

添加自定义属性

我使用这样的小帮手：

type CustomAttributeDataExt =
    static member Make(ctorInfo, ?args, ?namedArgs) = 
        { new CustomAttributeData() with 
            member __.Constructor =  ctorInfo
            member __.ConstructorArguments = defaultArg args [||] :> IList<_>
            member __.NamedArguments = defaultArg namedArgs [||] :> IList<_> }

可选的args和namedArgs使得更简单，代码更清晰。当我想添加一个自定义属性时，如果有几个，我通常会添加几个类型的帮助器，以使代码更清晰：

module Attributes =
let MakeActionAttributeData(argument:string) =
    CustomAttributeDataExt.Make(typeof<ActionAttribute>.GetConstructor(typeof<string>),
                                [| CustomAttributeTypedArgument(typeof<ActionAttribute>, argument) |])

open Attributes
myProperty.AddCustomAttribute <| Attributes.MakeActionAttributeData("attributeData")

添加一个调用基类型

的构造函数

同样，我有一些小帮手反思：

    type Type with
    member x.GetConstructor(typ) =
        x.GetConstructor([|typ|])

    member x.TryGetConstructor(typ:Type) =
        x.GetConstructor(typ) |> function null -> None | v -> Some v

    ...

像往常一样创建您提供的类型（记住设置IsErased = false），然后

    //string ctor
    match providedType.TryGetConstructor(typeof<string>) with
    | None -> failwithf "No string constructor found for type: %s" providedType.Name
    | Some ctor -> let stringCtor = ProvidedConstructor([ProvidedParameter("theString", typeof<string>)], InvokeCode=Expr.emptyInvoke, BaseConstructorCall = fun args -> ctor, args)
                   providedController.AddMember(stringCtor)

我认为其他部分应该在其他地方记录，特别是添加普通成员等。

生成类型提供程序：高级示例

1 个答案:

添加自定义属性

添加一个调用基类型