有没有办法在春天迭代列表或地图?我无法在网上找到任何参考资料。
这是我定义的 -
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-2.5.xsd">
<util:list id="myList" value-type="java.lang.String">
<value>foo</value>
<value>bar</value>
</util:list>
<bean id="bean1" class="com.StaticClass" factory-method="createObject">
<constructor-arg value="foo" />
</bean>
<bean id="bean2" class="com.StaticClass" factory-method="createObject">
<constructor-arg value="bar" />
</bean>
<bean id="myMap" class="java.util.HashMap">
<constructor-arg index="0" type="java.util.Map">
<map key-type="java.lang.Integer" value-type="java.lang.Float">
<entry key="foo" value-ref=bean1 />
<entry key="bar" value-ref=bean2 />
</map>
</constructor-arg>
</bean>
我想使用以下逻辑迭代这个列表并创建一个地图,而不是创建多个bean对象 -
for (String m : myList) {
myMap.put(m, MyStaticFactory.createObject(m));
}
我可以在春天这样做吗?
答案 0 :(得分:1)
如何使用spring @Configuration(请参阅this link中的说明)而不是spring XML?
@Configuration
public class MySpringContext {
@Bean(name="myMap")
public Map<String, StaticClass> getMyMapBean() {
// I'm not sure where you create 'm' but if that's a bean you can inject it to the class and use it.
for (String m : myList) {
myMap.put(m, MyStaticFactory.createObject(m));
}
}
}
@Configuration类是一种以编程方式而不是XML来定义bean的方法,这使您可以更灵活地执行任何操作。
答案 1 :(得分:0)
这样的事情可能是:
public class MyMapBean extends HashMap {
public MyMapBean(List<String> beanNames) {
for(name: beanNames) put(name, MyStaticFactory.createObject(name));
}
}
然后在应用程序上下文中:
<bean id="myMap" class="MyMapBean">
<constructor-arg index="0" value-ref="myList" />
</bean>