如何在过滤器中使用两个参数?
var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
filter: function(object) {
return object.id != source1 && source2;
}
}).id;
因为我的过滤器只考虑参数'source1'...
答案 0 :(得分:1)
请确保在第二部分中添加比较object.id != source2
var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
filter: function(object) {
return object.id != source1 && object.id != source2;
}
}).id;