Question

我正在尝试定义发送推送通知的云代码方法，但是我很难声明并调用方法。我需要一个方法来获取3个字符串参数tracking，slug和channel我知道如何用Java或其他OOP语言编写这些参数。

private void sendNotification(String tracking, String slug, String channel)

并致电sendNotification("someTracking", "someSlug", "someChannel");

我如何在Parse JS SDK中编写这些方法？

Answer 1

您可以声明Bjorn发布的指南（https://www.parse.com/docs/cloud_code_guide#cloud_code）中概述的Cloud Code功能。在这种情况下，为了帮助您，下面是一个方法定义的示例，其行为将如您所愿。

/**
 * Send Push Notification
 * Required:
 * tracking                          -- Tracking String
 * slug                              -- Slug String
 * channel                           -- Channel String
 */
Parse.Cloud.define("sendNotification", function(request, response) {
               // Obviously you don't need to assign these variables, but this is how you access the parameters passed in
               var tracking = request.params.tracking;
               var slug = request.params.slug;
               var channel = request.params.channel;
               // Send your push notification here, I'm not gonna write the whole thing for you! :)
                   // In the callback of your push notification call:
                   response.success();
                   // For a successful send and response.error() if it fails or an error occurs
               });

要在客户端中调用此方法，假设您使用的是java，因为您在问题语句中使用了java语法，则可以按照“云代码指南”（前面引用）中的说明使用此模式：

HashMap<String, Object> params = new HashMap<String, Object>();
params.put("tracking", "TRACKING_STRING");
params.put("slug", "SLUG_STRING");
params.put("channel", "CHANNEL_STRING");
ParseCloud.callFunctionInBackground("sendNotification", params, new FunctionCallback<Float>() {
   void done(ParseException e) {
       if (e == null) {
          // Your function was successful
       } else {
          // Your function failed, handle the error here
       }
   }
});

但是，如果您只是尝试从客户端发送推送通知，则应该只使用此处概述的Parse内置函数：https://parse.com/docs/push_guide#sending/Android

解析函数声明Javascript

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