Question

我有一个作业表，其中包含薪水列。

如何将薪水分成10,000美元的小组，然后计算每个桶中有多少个工作？

使用Rails活动记录的答案更可取，但考虑到困难，我也会接受原始SQL答案。

开始数据

Jobs

id      salary (integer)
-----------------
1       93,530
2       72,400
3       120,403
4       193,001
...

结果数据

bucket               job_count
----------------------------
$0 - $9,999          0
$10,000 - $19,999    0
$20,000 - $29,999    3
$30,000 - $39,999    5
$40,000 - $49,999    12

Answer 1

从SQL的角度来看，有几种方法。这是一个。

-- First, create a report table (temporarily here, but could be permanent):

create table salary_report (
  bucket      integer,
  lower_limit integer,
  upper_limit integer,
  job_count   integer
);

-- populate the table
-- note this could (and probably should) be automated, not hardcoded
insert into salary_report values (1,00000,09999,0);
insert into salary_report values (2,10000,19999,0);
insert into salary_report values (3,20000,29999,0);
insert into salary_report values (4,30000,39999,0);
insert into salary_report values (5,40000,49999,0);

-- set correct counts
update salary_report as sr
  set job_count = (
    select count(*)
    from jobs as j
    where j.salary between sr.lower_limit and sr.upper_limit
    );

-- finally, access the data (through activerecord?)
-- note: not formatted as dollar amounts
select concat( sr.lower_limit,' - ',sr.upper_limit) as range, job_count, bucket
from salary_report
order by bucket;

-- drop table if required
drop table salary_report;

我试图保持SQL泛型，但确切的语法可能会因您的RDBMS而异。 没有提供SQL小提琴，因为它今天似乎已被打破。

Answer 2

这是另一种基于SQL的解决方案。

获取每个薪水的桶如下：

select 
  FLOOR(salary/10000) as bucket
from jobs

使用GROUP BY进行计数：

select 
  bucket, 
  count(*)
from (
    select FLOOR(salary/10000) as bucket
    from jobs
) as t1
GROUP BY bucket

最后，添加范围而不是桶号：

select 
  CONCAT('$', FORMAT(bucket*10000,0), ' - $', FORMAT((bucket+1)*10000-1,0)) as range, 
  job_count
from ( 
    select bucket, count(*) as job_count
    from (
        select FLOOR(salary/10000) as bucket
        from jobs
    ) as t1
    GROUP BY bucket
) as t2

请注意，使用的函数适用于MySQL。因人而异。

Rails SQL - 创建存储桶，并获取每个存储桶中的记录计数

2 个答案: