如何在不添加ghost空间的情况下将数组中的字符串添加到scandir

时间:2014-12-31 22:59:28

标签: php mysqli scandir

当我从数组$rawgendir=$row['gendir'];中获取目录字符串时 scandir返回错误

"Warning: scandir( ALABAMA/CITIES ABBEVILLE - ALABAMA REVENUE ENFORCEMENT/ , ALABAMA/CITIES ABBEVILLE - ALABAMA REVENUE ENFORCEMENT/ ): The system cannot find the path specified. (code: 3)"

在var $ dir中明确定义路径,只是不适用于我想要创建的内容。在这种情况下,图像的搜索引擎

我认为问题是,我在scandir( ALABAMA/...)得到一个幽灵空间而且我不知道如何。我已经在这工作了很长时间,因为我绝对不是程序员。

 //$searchstring PULLED FROM _POST
 $db_conx = (MYSQLi CONNECTION)
 $sql="SELECT *  FROM `main` WHERE CONVERT(`title` USING utf8) LIKE '%" . $SearchString . "%'";

$result = mysqli_query($db_conx, $sql);

//-create while loop and loop through result set
while($row=mysqli_fetch_array($result)){

$patchtitle=$row['title'];
$id=$row['id'];
$patchpath=$row['dir'];
$rawgendir=$row['gendir'];
echo $rawgendir;

这一行

echo $rawgendir;

打印出ALABAMA/CITIES ABBEVILLE - ALABAMA REVENUE ENFORCEMENT/ 没有神秘的空间

// $dir = ("ALABAMA/CITIES ABBEVILLE   -   ALABAMA REVENUE ENFORCEMENT/");

$fileList = scandir($rawgendir);
//echo $dir;
//echo $rawgendir;
//-display the result o
 echo '
    <table width="864" height="220" border="2">
    <tr>
    <td width="214" height="152"><center>
    <img src="'.$patchpath.' " width="220" height="200" />
    </center></td>
    <td width="632"<h3>Patch: '. $patchtitle . '</h3></td>
     </tr>
    </table> </br>
    ';
}

0 个答案:

没有答案