Question

我需要如果子查询结果为null，那么它将替换为' - '。我试过这个

REPLACE ( string_expression , string_pattern , string_replacement )

REPLACE((SELECT [StandNo] FROM [dbo].[BusStand] where id=b.[ReturnStand]), char(0), '-')

但没有解决方案，因为我认为它将子查询作为string_expression。

(SELECT isnull([StandNo],'-') FROM [dbo].[BusStand] where id=b.[ReturnStand])以下的解决方案也无效。

对不起家伙我发现问题不在于子查询b.[ReturnStand]是空的，因为它选择零行并在结果中放置null。我的查询是这样的。

SELECT b.[Id],
       b.[Date],
       (SELECT [BusId]
        FROM   [dbo].[Bus]
        WHERE  id = [breakDownBusNo])           AS Bus,
       (SELECT [RouteNo]
        FROM   [dbo].[Route]
        WHERE  id = bl.[routeNo])               AS [Route No],
       (SELECT [StandName]
        FROM   [dbo].[BusStand]
        WHERE  id = b.[stand])                  AS [Breakdown Stand],
       b.[DeadKm]                               AS [Distance From Depo],
       (SELECT COALESCE([StandNo], 0)
        FROM   [dbo].[BusStand]
        WHERE  id = b.[ReturnStand])            [On Route Stand],
       COALESCE([ReturnKm], 0)                  AS [Distance of on route place],
       ( b.[DeadKm] + COALESCE([ReturnKm], 0) ) AS Total
FROM   [dbo].[BreakDown] AS b
       INNER JOIN [dbo].[Bus Log] AS bl
               ON b.BusLogId = bl.Id
       INNER JOIN [dbo].[DriverAttendance] AS da
               ON da.Id = b.DrvrAttnDnceIdLog

请不要进入查询复杂性我只需要显示我在哪里使用它。现在我如何在路线展台上用' - '替换null。

Answer 1

您的语法错误您需要在string_expression

中添加列名或变量

SELECT REPLACE(isnull([StandNo],0),'0', '-') FROM [dbo].[BusStand] 
where id=b.[ReturnStand]

或更好的方式

无需使用Replace

....IN
( SELECT isnull([StandNo],'-') FROM [dbo].[BusStand] 
where id=b.[ReturnStand] )

Answer 2

请尝试：

(SELECT ISNULL([StandNo] ,  '-') FROM [dbo].[BusStand] where id=b.[ReturnStand])

Answer 3

使用COALESCE功能

SELECT COALESCE((SELECT [StandNo] FROM [dbo].[BusStand] where id=b.[ReturnStand]) , '-')
FROM [dbo].[tableA] AS b;

Answer 4

你可以直接这样做

SELECT b.[Id],
       b.[Date],
       (SELECT [BusId]
        FROM   [dbo].[Bus]
        WHERE  id = [breakDownBusNo])           AS Bus,
       (SELECT [RouteNo]
        FROM   [dbo].[Route]
        WHERE  id = bl.[routeNo])               AS [Route No],
       (SELECT [StandName]
        FROM   [dbo].[BusStand]
        WHERE  id = b.[stand])                  AS [Breakdown Stand],
       b.[DeadKm]                               AS [Distance From Depo],

   **** (SELECT isnull([StandNo], '-')
    FROM   [dbo].[BusStand]
    WHERE  id = b.[ReturnStand])            [On Route Stand], ****


    COALESCE([ReturnKm], 0)                  AS [Distance of on route place],
   ( b.[DeadKm] + COALESCE([ReturnKm], 0) ) AS Total
    FROM   [dbo].[BreakDown] AS b
   INNER JOIN [dbo].[Bus Log] AS bl
           ON b.BusLogId = bl.Id
   INNER JOIN [dbo].[DriverAttendance] AS da
           ON da.Id = b.DrvrAttnDnceIdLog

替换SQL中的子查询结果

4 个答案: