我的问题是如何设置单击我的列表中的项目,因为在列表片段中它需要具有特定的ID是android:list所以我不知道如何使用它。
我有这个布局:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:fab="http://schemas.android.com/apk/res-auto"
android:layout_width="match_parent"
android:layout_height="match_parent">
<ListView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:id="@id/android:list"
android:layout_alignParentTop="true"
android:layout_alignParentLeft="true"
android:layout_alignParentStart="true"
android:layout_alignParentBottom="true" />
<TextView
android:id="@android:id/empty"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:textSize="30sp"
android:text="" />
<com.getbase.floatingactionbutton.AddFloatingActionButton
android:id="@+id/semi_transparent"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
fab:fab_plusIconColor="@color/primaryColorDark"
fab:fab_colorNormal="@color/primaryColor"
fab:fab_colorPressed="@color/AccentColor"
android:layout_alignParentBottom="true"
android:layout_alignParentRight="true"
android:layout_alignParentEnd="true" />
和这个列表片段:
public class F1_fr extends ListFragment {
View rootview;
TextView textView1;
ArrayAdapter<String> aa;
ArrayList<String> arrayList = new ArrayList<String>();
SQLiteDatabase db;
ListView listView;
@Override
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
rootview=inflater.inflate(R.layout.f1_lay,container,false);
textView1=(TextView)rootview.findViewById(R.id.textView1);
db = getActivity().openOrCreateDatabase("testDB2", Context.MODE_PRIVATE, null);
db.execSQL("CREATE TABLE IF NOT EXISTS test2(mac VARCHAR,mdp VARCHAR,obj VARCHAR);");
aa = new ArrayAdapter<String>(getActivity(),
android.R.layout.simple_list_item_1, arrayList);
setListAdapter(aa);
Cursor cursor = db.rawQuery("SELECT * FROM test2", null);
// Toast.makeText(myContext, ""+cursor.getCount(), Toast.LENGTH_LONG).show();
if (cursor.moveToFirst())
{
do
{
arrayList.add(cursor.getString(2));
} while (cursor.moveToNext());
}
rootview.findViewById(R.id.semi_transparent).setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent intent=new Intent(getActivity(),ajout.class);
startActivityForResult(intent, 2);
}
});
return rootview;
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data)
{
super.onActivityResult(requestCode, resultCode, data);
if(requestCode == 2)
{
//String message=data.getStringExtra("MESSAGE");
Intent intent=new Intent(getActivity(),qr.class);
startActivity(intent);
}
}
@Override
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);
}
}
答案 0 :(得分:0)
这样的事情可以解决问题(至少我认为这是你想要做的事情)
在onCreateView()
中((ListView) rootView.findViewById(android.R.id.list)).
setOnItemClickListener(new OnItemClickListener(){
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id){
//Do what you want when you click on an item
}
}
因为我没有时间解释它,所以会发表评论,但看起来很草率所以认为答案会更好。