Question

我想从字符串中删除一些特定的单词和短语，然后我在Strip specific words from string进行了讨论。

我创建了一系列禁用词： $ wordlist = array（＆＃34; bayes＆＃34;，＆＃34; full＆＃34;，＆＃34;大于＆＃34;）;

我的示例字符串是：

$string= "my bayesian results are full of bayes and greater than anything else";

如果我应用以下代码：

foreach ($wordlist as &$word) {
    $word = '/\b' . preg_quote($word, '/') . '\b/';
}
$string = preg_replace($wordlist, '', $string);

结果是：我的贝叶斯结果比其他任何东西都要大[删除单词：贝叶斯，全部]

而我想要的结果是：我的结果是和其他任何东西[删除单词：贝叶斯，贝叶斯，完整，大于]

请注意，我希望禁词“贝叶斯”＃39;应该删除“贝叶斯”这个词。同样。

Answer 1

尝试在结束边界之前添加.*?。它会非贪婪地匹配，直到到达边界。
就像这样 -

$word = '/\b' . preg_quote($word, '/') . '.*?\b/';
                                          ^^^

输出 -

my  results are  of  and  anything else

Answer 2

也许这个：

$string = "my bayesian results are full of bayes and greater than anything else";
$forbidden = array('/bayes(\w+)/','/full(\w+)/');
$result = preg_replace($forbidden , array(), $string);
print_r($result);

此代码获取字符串，尝试将一组正则表达式模式（$ forbidden）与字符串匹配，并用空值替换它们。

它查找以bayes或full开头的单词，并在找到空格时停止查找。

Answer 3

首先将字符串拆分为单词，然后针对每个被禁止的单词检查每个单词，并在必要时将其删除。

$string = "my bayesian results are full of bayes and greater than anything else";
$banned_words = array("bayes", "full", "greater than");
$words = explode(' ',$string);

foreach($words as $key => $word) {
    foreach($banned_words as $banned_word) {
        if(false !== stripos($word,$banned_word)) {
            unset($words[$key]);
            break;
        }
    }
}

$string = implode(' ',$words);

最后删除任何1+单词完整匹配

print str_ireplace($banned_words,'',$string);

从字符串中删除特定的单词/短语

3 个答案: