Question

我已经使用了laravel中的验证器，但是如果用户不是经过身份验证的用户，我想添加自定义规则。这就是我所做的：

  public function postSignIn(){
    $validator = Validator::make(Input::all(),
        array(
            'email'     => 'required|email',
            'password'  => 'required'
        )
    );
    if($validator->fails()){
        //return error message
        return Redirect::to('account/signin')
            ->withErrors($validator)
            ->withInput(Input::except('password'));
    }
    else{
        $remember = (Input::has('remember')) ? true:false;
        $auth = Auth::attempt(array(
                'email'     => Input::get('email'),
                'password'  => Input::get('password'),
                'active'    => 1
            ),$remember
        );

        if($auth){
            return Redirect::intended('/')
                        ->with('global', 'Welcome');
        }
        else{
            return Redirect::to('account/signin')
                ->withErrors($validator, 'login');
        }
    }

这是我显示错误的视图

     @if ($errors -> has())
         <div class="alert-danger alert-dismissible fade in" role="alert" style="padding: 0.5em;">
             <button type="button" class="close" data-dismiss="alert"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>
              @foreach($errors->all() as $error)

                   {{ $error }}<br />
              @endforeach

          </div>
     @endif

表单的验证工作正常，但我有问题显示未经身份验证的用户的错误。所以，任何帮助都会非常感激。

Answer 1

迟到但在错误消息包中添加自定义消息的另一个解决方案是：

<强>控制器

$rules = array(
        'email' => 'required|exists:users,email|email|max:32',
        'password' => 'required|max:20'
    );
    $validator = Validator::make($request->all(),$rules);


    $email = $request->email;
    $password = $request->password;

    $validateUser = new user();
    $users = $validateUser::where('email', $email)->get();
    if($users->isEmpty()){
        $validator->getMessageBag()->add('email', 'Invalid Email Address');    
        return redirect('home')->withErrors($validator);
    }
    foreach ($users as $user) {
        $data = $user->showAdminData();
        if($user->role_id!=1){
            $validator->getMessageBag()->add('email', 'Unauthorised access');
        }
        if(Crypt::decrypt($user->password)!==$password){
            $validator->getMessageBag()->add('password', 'Invalid Password');
        }
    }
    return redirect('home')->withErrors($validator);

查看

<div class="form-group{{ $errors->has('email') ? ' has-error' : '' }}"> <label class="col-md-4 control-label">E-Mail Address</label> <div class="col-md-6"> <input type="email" class="form-control" name="email" value="{{ old('email') }}"> @if ($errors->has('email')) <span class="help-block"> <strong>{{ $errors->first('email') }}</strong> </span> @endif </div> </div> <div class="form-group{{ $errors->has('password') ? ' has-error' : '' }}"> <label class="col-md-4 control-label">Password</label> <div class="col-md-6"> <input type="password" class="form-control" name="password"> @if ($errors->has('password')) <span class="help-block"> <strong>{{ $errors->first('password') }}</strong> </span> @endif </div> </div>

Answer 2

试试这样：

     <?php $message = Session::get('message'); $errors = Session::get('errors'); $status = Session::get('status'); ?>

      @if($message)

              <div class="infobox {{$message['type']}}-bg animated flipInY" style="margin-top:30px;">
                      //your functionalities
              </div>

      @endif

Answer 3

这可能有助于实现您的目标。当用户无法进行身份验证时，我在登录表单中使用了以下代码进行自定义错误。

    //Code in controller
   if(Auth::attempt(Input::only('email','password')))
        {

            return Redirect::to('/');
        }
       //put your message in a session
        Session::flash('msg', "Invalid email or password. Please Try again! ");
        return Redirect::back();    
   //Code in view
      <div class="error">
        @if (Session::has('msg'))
            {{ Session::get('msg') }}
        @endif
    </div>

在Laravel中添加自定义错误？

3 个答案: