我有下表,
id | add_card_id | rate | category | category_count | counts | total
7597 | 723 | 3 | 7 | 1 | 300 | 108
7596 | 723 | 3 | 9 | 1 | 500 | 180
7594 | 723 | 3 | 11 | 1 | 400 | 240
7593 | 723 | 5 | 10 | 2 | 400 | 240
7593 | 723 | 5 | 13 | 2 | 400 | 240
我想获得total
(列名)的总和,其中rate
相同,但总和只包含第n个。具有最大总数的行,nth由category_count
(列名称)定义。
例如,前三列的比率是3并且category_count是1,因此前三行的总和(总)是240,因为240> 180> 108,在最后两行的情况下,rate是5,category_count是2,所以240 + 240 = 480,我想要720 = 240(从前三行)+ 480(从最后两行)。
我尝试了以下查询
SELECT SUM(total)
FROM (SELECT MAX(total)
FROM tableName
GROUP BY rate, category_count) as newTable
它给了我240+ 240,所以如何通过category_count
(列)给出限制?
答案 0 :(得分:0)
试试这个
select sum(cnt) from(select max(cnt)cnt from
(SELECT rate, category_count,total*count(*)cnt FROM tableName GROUP BY rate, category_count,total)temp group by rate, category_count)temp
答案 1 :(得分:0)
您可以通过动态分配变量来模拟MySql中的ROW_NUMBER和PARTITION BY
SELECT rate, SUM(total)
FROM
(
SELECT total, rate, category_count,
-- Row num counter, resets at each different rate
@row_num := IF(@prev_rate=rate, @row_num+1, 1) AS RowNum,
@prev_rate := rate -- Track to see if we are in the same rate
FROM tableName,
(SELECT @row_num := 1) x, -- Set initial value for @row_num and @prev_rate
(SELECT @prev_rate := '') y
-- Important, must keep rates together, then order by your requirement
ORDER BY rate ASC, total DESC
) ranked
WHERE ranked.RowNum <= ranked.category_count -- Your requirement of TOP N
GROUP BY rate;
以上返回
Rate Total
3 240
5 480
如果您执行SELECT SUM(total)
然后删除GROUP BY,您将获得720。
修改
似乎费率被定义为(我假设你的样本数据中有一个整数)
`rate` varchar(X) COLLATE utf8_unicode_ci
更改一行:
(SELECT @prev_rate := '' COLLATE utf8_unicode_ci) y
将临时跟踪变量设置为与列
相同的类型