Question

我有一个表单，其中包含从循环PHP数据生成的选项。我试图将选定的POST数据传递到同一页面进行处理。但是，出了点问题。我得到一个未定义的索引，print_r（$ _ POST）显示一个空数组。有人可以帮忙吗？

<!DOCTYPE html>
    <head>
        <title>Inventory Tables</title>
    </head>
<script src="../_js/jquery.min.js"></script>
<script src="../_js/jquery-ui.min.js"></script>
<body>

<?php //inventory mysql tables

ini_set('display_errors',1);  error_reporting(E_ALL);

require_once 'inventoryconfig.php';
$connection = new mysqli($db_hostname, $db_username, $db_password, $db_database);

if ($connection->connect_error) die($connection->connect_error);

$result = $connection->query("SHOW TABLES");

$table = array();
    while ($row = $result->fetch_row()){
        $table[] = $row[0];
     }

$count = count($table);
$all = "*";
?>

<?php  if ($_SERVER['REQUEST_METHOD'] == 'GET') {?>

<form action="<?php echo $_SERVER['PHP_SELF']?>" method="POST">
<select method="POST">
    <option value=\"$all\">--Select--</option>\n";
<?php for ($pointer = 0 ; $pointer < $count ; ++$pointer) {
    echo <<<_END
            <pre>
                <option name="$table[$pointer]" value="$table[$pointer]">$table[$pointer]</option>
            </pre>
_END;
    }

global $table;
global $pointer;

?>
</select>
<input type="submit" value="send">
</form>

<?php } else if ($_SERVER['REQUEST_METHOD'] == 'POST') {

$thisTable = $_POST['$table[$pointer]'];

print_r($_POST);
echo $thisTable;
}

$connection->close();
?>

</body>
</html>

未定义的索引：使用循环MySQL数据自我处理PHP表单

0 个答案: