Question

我希望用户能够创建不确定数量的问题。一旦用户创建了一个问题，我想要出现另一个问题（问题2），依此类推......

我该怎么做？

由于

Answer 1

我会做类似的事情：

function addClone() {
    var cloned = document.getElementById('test').cloneNode(true); //clone the element
    document.body.appendChild(cloned); //add the cloned element to the page
}

<div id='test'>iadwjoam</div>
<input type="checkbox" id="xxx" name="xxx" onchange="addClone()" />

cloneNode() - https://developer.mozilla.org/en-US/docs/Web/API/Node.cloneNode

Answer 2

你可以尝试这样的事情

HTML

<div class="input-container">
  <input class="question" placeholder="Question" type="text"/>
</div>

<div class="add-option">+</div>

JS

//click the '+' sign
$(".add-option").click(function(){

   //find the first input and clone it then append it to the container
   $(".input-container input:first").clone().appendTo(".input-container");

   //clear any value from the next input had there been any added
   $(".input-container input:last").val("");
});

FIDDLE

<强>更新

我遗漏了关于复选框的部分，从UI的角度来看，我认为你不需要一个复选框来完成这个，不确定它是否表明“这已经完成并且我想继续”但是这取决于你决定。这是一个新的小提琴

HTML

<div class="input-container">
  <input class="question" placeholder="Question" type="text"/>
</div>

<div class="add-option"><input type="checkbox"/></div>

JS

//click the checkbox
$(".add-option input[type=checkbox]").click(function(){

 //find the first input and clone it then append it to the container
 $(".input-container input:first").clone().appendTo(".input-container");

 //clear any value from the next input had there been any added
 $(".input-container input:last").val("");

 //reset the checkbox
 $(this).prop("checked", false);
});

NEW FIDDLE

Answer 3

在javascript中你可以这样做

var i = 0;

function addMore() {
  i++;
  var parentDiv = document.createElement("div");

  var childLabel = document.createElement("label");
  childLabel.appendChild(document.createTextNode("Enter Value " + i));

  var childTextBox = document.createElement("input");
  childTextBox.type = "text";
  childTextBox.id = "txtInput" + i;

  var childCheckBox = document.createElement("input");
  childCheckBox.type = "checkbox";
  childCheckBox.onchange = addMore;

  parentDiv.appendChild(childLabel);
  parentDiv.appendChild(childTextBox);
  parentDiv.appendChild(childCheckBox);
  document.body.appendChild(parentDiv);

}

<div>
  Add Items
  <input type="checkbox" onchange="addMore()">
</div>

希望这个帮助

Answer 4

这里或多或少会使用纯JavaScript做什么（请参阅说明评论）

＆＃13;

// Create a copy of a blank Question node
question_template = document.getElementById("questions").firstElementChild.cloneNode(true);
// A nice cloning wrapper
new_question = function(){return question_template.cloneNode(true);};
// Something to do when the user is finished putting in questions
alrt = function(){
    alert(Array.prototype.map.call(document.getElementById(
      "questions").getElementsByTagName("input"),
      function(elt){return elt.value;}));
};
// Hook for when text is placed in textbox
addnew = function(){
    // Remove the event listener (If you don't do this, then on every
    //   keystroke a new box will be created
    document.getElementById("questions").lastElementChild.oninput = function(event){};
    // Add a new line
    document.getElementById("questions").appendChild(document.createElement("br"));
    // Add a new question box
    document.getElementById("questions").appendChild(new_question());
};

＆＃13;

<div id="questions">
<input type="text" oninput="addnew()"/>
</div>
<input type="button" value="Done" onclick="alrt()"/>

＆＃13;

更新：我刚刚在主要帖子的评论部分看到了您的详细说明。您可以使用以下内容实现：

＆＃13;

// Create a copy of a blank Question node
question_template = document.getElementById("questions").firstElementChild.cloneNode(true);
// A nice cloning wrapper
new_question = function(){return question_template.cloneNode(true);};
// Something to do when the user is finished putting in questions
alrt = function(){
    alert(Array.prototype.map.call(document.getElementById(
      "questions").getElementsByTagName("input"),
      function(elt){return elt.value;}));
};
// Hook for when text is placed in textbox
addnew = function(){
    // Add a new line
    document.getElementById("questions").appendChild(document.createElement("br"));
    // Add a new question box
    document.getElementById("questions").appendChild(new_question());
};

＆＃13;

<div id="questions">
    <input type="text"/>
    </div>
<input type="button" value="Add Another" onclick="addnew()"/>
    <input type="button" value="Done" onclick="alrt()"/>

＆＃13;

这可以通过具有正确事件的大多数input元素来实现。如果您需要，W3学校有a nice reference。

如何通过复选框复制div？

4 个答案: