Question

 //angularjs_DB.php
<?php
	$con=mysqli_connect("localhost","root","","hris_iit");
	// Check connection
	if (mysqli_connect_errno())
	{
		echo "Failed to connect to MySQL: " . mysqli_connect_error();
	}

	$sql="SELECT idemployee, current_designation,current_salary,previous_designation,previous_salary,reason,effective_date from promotion";
	$result = $con->query($sql);
	
     // output data of each row
	 $output="[";
     while($row = $result->fetch_array(MYSQLI_ASSOC)) {
		if($output!="["){$output .=",";}
		$output .='{"idemployee":"' .$row["idemployee"] .'",';
		$output .='"current_designation":"' .$row["current_designation"] .'",';
		$output .='"current_salary":"' .$row["current_salary"] .'",';
		$output .='"previous_designation":"' .$row["previous_designation"] .'"}';
         //echo "<br> id: ". $row['idemployee']. $row['current_designation']. $row['current_salary']. $row['previous_designation'];
		
	}
	$output .="]";
	mysqli_close($con);
	
	echo ($output);
	//return ($output);

?>

<!DOCTYPE html>

<html>
<head>
	<script src="angular.min.js">
	</script>
</head>
<body>
	
	<div data-ng-app="" data-ng-controller="customerController">
		<table>
			<tr>
				<td><b>idemployee</b></td>
				<td><b>current_designation</b></td>
				<td><b>current_salary</b></td>
				<td><b>previous_designation</b></td>
			</tr>
			<tr data-ng-repeat="x in names">
				<td>{{x.idemployee}}</td>
				<td>{{x.current_designation}}</td>
				<td>{{x.current_salary}}</td>
				<td>{{x.previous_designation}}</td>
			</tr>
		</table>
	</div>
	
	<script>
		function customerController($scope,$http){
			$http.get("http://localhost/startup/angularjs_DB.php")
			.success(function(response){$scope.names=response;});
		
		}
	</script>
	<!-- The code above can also be used to fetch data from a database -->
</body>


<html>

Problem in output of the html code that are not values from Database !!!
Output likes following: 
idemployee  current_designation current_salary  previous_designation
{{x.idemployee}}    {{x.current_designation}}   {{x.current_salary}}    {{x.previous_designation}}

Answer 1

这是一个演示，演示如何使用PHP http://plnkr.co/edit/p8kDN3Mj1AcmR6ml312H?p=preview

生成的字符串

myApp.controller('customerController',function ($scope,$http){
        //  $http.get("http://localhost/startup/angularjs_DB.php")
        //  .success(function(response){$scope.names=response;});
        $scope.names = JSON.parse('[{"idemployee": 1}, {"idemployee":2}]')
        });

我没有写出整个JSON，但你可以看到它是如何工作的

另外，我不编写PHP，所以我不知道怎么做，但你不需要循环结果集。您应该能够将整个集合作为关联数组并将其传递给json_encode

无法从数据库中选择数据

1 个答案: