Question

我想执行一个选择，找到每个有$ Value（SomeNumber）$的行。值和 SomeNumber 部分是动态的。

如何构建符合此条件的选择？

我试着这样：

DECLARE @VALUE VARCHAR(255)
SET @VALUE = 'Badass(5)' -- it could Badass, Badass(XXX) or Badass(XX)
SELECT Txt FROM Employers where Txt LIKE '%$' + @VALUE + '$%' OR 
    TxT LIKE '%$' + @VALUE + '\(\d{2}\)$%'

Answer 1

如果你想要Regex并且可以使用CLR，我会使用Sql#。

根据问题中的可用内容不太确定您的搜索规则，但这可能会导致某处：

  declare @value varchar(255) = 'Badass(5)' -- it could Badass, Badass(XXX) or Badass(XX)/

  declare @parenthesis int = isnull(nullif(charindex('(',@value),0),256)
  declare @search_str varchar(255) = '%$'+left(@value,@parenthesis-1)
  declare @somenumber varchar(255) = case @parenthesis when 256 then '%$%' else '([0-9]%)$%' end
  declare @search varchar(255) = @search_str + @somenumber

  --select value=@value, search_str=@search_str, somenumber=@somenumber, search=@search

select StringMatch=case when rowtxt like @search then 1 else 0 end
  , value=@value
  , rowtxt
from (select rowtxt='This is SamSaffron $Badass$'
  union all select 'This is BrentO $Badass(12)$'
  union all select 'This is AaronBertrand $Badass(20141222)$ '
  union all select 'This is SqlZim $Not As Badass(N)$ '
  union all select 'This is SqlZim $Badass(ButNoNumber)$ '
  union all select 'This is SqlZim $Badass(1Number)$ '
) i

@value = 'BadAss(5)' returns

IsMatch     value            rowtxt
----------- ---------------- -----------------------------------------
0           Badass(5)        This is SamSaffron $Badass$
1           Badass(5)        This is BrentO $Badass(12)$
1           Badass(5)        This is AaronBertrand $Badass(20141222)$ 
0           Badass(5)        This is SqlZim $Not As Badass(N)$ 
0           Badass(5)        This is SqlZim $Badass(ButNoNumber)$ 
1           Badass(5)        This is SqlZim $Badass(1Number)$

@value = 'BadAss' returns

IsMatch     value            rowtxt
----------- ---------------- -----------------------------------------
1           Badass           This is SamSaffron $Badass$
1           Badass           This is BrentO $Badass(12)$
1           Badass           This is AaronBertrand $Badass(20141222)$ 
0           Badass           This is SqlZim $Not As Badass(N)$ 
1           Badass           This is SqlZim $Badass(ButNoNumber)$ 
1           Badass           This is SqlZim $Badass(1Number)$

Answer 2

MSSQL对正则表达式的内置支持很差，有两个选项

a）创建CLR存储例程，请参阅http://msdn.microsoft.com/en-us/magazine/cc163473.aspx

b）在TSQL中使用VBScript.RegExp，请参阅http://blogs.msdn.com/b/khen1234/archive/2005/05/11/416392.aspx

两者都至少需要MSSQL 2005。

SQL Server - 选择使用like和某种正则表达式

2 个答案: