将出勤单选按钮提交到数据库

Question

我正在制作这个系统并且遇到了需要帮助的问题 我的数据库有表格attandence字段     att_id s_no std_reg_no std_name semester_id total_classes present absent 我已经制作了这个表格，其中显示了特定学期的学生和用于标记学生是否在场的单选按钮。我通过数组使用了无线电名称中的s_no学生代码

    <form method="POST" enctype="multipart/form-data" >
<input type="hidden" name="chk" value="update">
<table border="groove" cellpadding="15px">
<tr>
<td>s.no</td>
<td>Reg. No</td>
<td>name</td>
<td>Present</td>
</tr>

<?php
while ($row = mysql_fetch_assoc($rs)){
$id=  $row['s_no'];
$no[]=  $row['std_reg_no'];
echo "<tr><td>";
echo $row['s_no']."</td><td>";  
echo $row['std_reg_no']."</td><td>";
echo $row['std_name']."</td>";
echo "<td> <input type='radio' name='attend[$id]' value='present' >Present &nbsp; <input type='radio' name='attend[$id]' value='ab'>absent</td></tr>";
}

echo "</table>";
echo "<input type='submit' name='btnAbsent' value='submit'>";

echo a;
?>
</form>

我想在php中做的是将每个radiobutton（如果存在）添加+1以呈现并且如果不存在+！请不要有人帮忙

Answer 1

试试这个，如果你选择任何人作为礼物，我增加+1，如果你选择任何人作为缺席，我减少-1 ...

数据库表结构查询

CREATE TABLE IF NOT EXISTS `attendance` (
  `att_id` varchar(255) NOT NULL,
  `s_no` varchar(255) NOT NULL,
  `std_reg_no` varchar(255) NOT NULL,
  `std_name` varchar(255) NOT NULL,
  `semester_id` varchar(255) NOT NULL,
  `total_classes` varchar(255) NOT NULL,
  `present` int(255) NOT NULL DEFAULT '0',
  `absent` int(255) NOT NULL DEFAULT '0'
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

<form method="POST" enctype="multipart/form-data" >
<input type="hidden" name="chk" value="update">
<table border="groove" cellpadding="15px">
<tr>
<td>s.no</td>
<td>Reg. No</td>
<td>name</td>
<td>Present</td>
</tr>

<?php
include_once("yourconfig.php"); //add here your db config file
extract($_POST);
//After Click on Submit Call this
if(isset($btnAbsent))
{
	foreach($attend as $atn_key=>$atn_value)
	{
		if($atn_value=="present")
		{
			$upd_qry="UPDATE attendance SET present=present+1 where s_no='".$atn_key."'";
			mysql_query($upd_qry);
		}
		elseif($atn_value=="absent")
		{
			$upd_qry="UPDATE attendance SET absent=absent-1 where s_no='".$atn_key."'";
			mysql_query($upd_qry);
		}
	}
}


//Default call this
$check_exist_qry="select * from attendance";
$rs=mysql_query($check_exist_qry);
$total_found=mysql_num_rows($rs);
while ($row = mysql_fetch_assoc($rs))
{
	$id=  $row['s_no'];
	$no[]=  $row['std_reg_no'];
	echo "<tr><td>";
	echo $row['s_no']."</td><td>";  
	echo $row['std_reg_no']."</td><td>";
	echo $row['std_name']."</td>";
	echo "<td> <input type='radio' name='attend[$id]' value='present' >Present &nbsp; <input type='radio' name='attend[$id]' value='absent'>absent</td></tr>";
}

echo "</table>";
echo "<input type='submit' name='btnAbsent' value='submit'>";
?>
</form>

如果您发现这是一个有用的方法，请将此答案作为正确答案，并对此解决方案进行投票