最近的Rust变化使得“特质对象”对我来说更加突出,但我只是模糊地掌握了什么让某些东西成为特质对象。特别是一个变化是upcoming change允许特征对象将特征实现转发到内部类型。
给定一个特征Foo
,我很确定Box<Foo>
是一个特征对象。 &Foo
也是特质对象吗?那些其他智能指针的内容如Rc
或Arc
呢?我怎样才能创建自己的类型作为特征对象呢?
reference只提到一次特征对象,但没有提到定义。
答案 0 :(得分:44)
当您有指向特征的指针时,您有特征对象。
Box
,Arc
,Rc
和参考&
都是其核心指针。在定义“特质对象”方面,它们以相同的方式工作。
“特质对象”是Rust对dynamic dispatch的看法。 这是一个我希望有助于显示特征对象的例子:
// define an example struct, make it printable
#[derive(Debug)]
struct Foo;
// an example trait
trait Bar {
fn baz(&self);
}
// implement the trait for Foo
impl Bar for Foo {
fn baz(&self) { println!("{:?}", self) }
}
// This is a generic function that takes any T that implements trait Bar.
// It must resolve to a specific concrete T at compile time.
// The compiler creates a different version of this function
// for each concrete type used to call it so &T here is NOT
// a trait object (as T will represent a known, sized type
// after compilation)
fn static_dispatch<T>(t: &T) where T:Bar {
t.baz(); // we can do this because t implements Bar
}
// This function takes a pointer to a something that implements trait Bar
// (it'll know what it is only at runtime). &dyn Bar is a trait object.
// There's only one version of this function at runtime, so this
// reduces the size of the compiled program if the function
// is called with several different types vs using static_dispatch.
// However performance is slightly lower, as the &dyn Bar that
// dynamic_dispatch receives is a pointer to the object +
// a vtable with all the Bar methods that the object implements.
// Calling baz() on t means having to look it up in this vtable.
fn dynamic_dispatch(t: &dyn Bar) {
// ----------------^
// this is the trait object! It would also work with Box<dyn Bar> or
// Rc<dyn Bar> or Arc<dyn Bar>
//
t.baz(); // we can do this because t implements Bar
}
fn main() {
let foo = Foo;
static_dispatch(&foo);
dynamic_dispatch(&foo);
}
为了进一步参考,有一个很好的Trait Objects chapter of the Rust book
答案 1 :(得分:2)
简短答案:您只能将对象安全的特征变成特征对象。
对象安全特征:不能解析为具体实现类型的特征。实际上,有两个规则控制特征是否是对象安全的。
任何满足这两个规则的特征都可以用作特征对象。
对象安全的特征示例可以用作特征对象:
trait Draw {
fn draw(&self);
}
不能用作特征对象的特征示例:
trait Draw {
fn draw(&self) -> Self;
}
有关详细说明:https://doc.rust-lang.org/book/second-edition/ch17-02-trait-objects.html
答案 2 :(得分:1)
Trait 对象是动态调度的 Rust 实现。动态分派允许在运行时选择多态操作(特征方法)的一种特定实现。动态分派允许非常灵活的架构,因为我们可以在运行时交换函数实现。但是,与动态分派相关的运行时成本很小。
保存 trait 对象的变量/参数是胖指针,由以下组件组成:
struct Point {
x: i64,
y: i64,
z: i64,
}
trait Print {
fn print(&self);
}
// dyn Print is actually a type and we can implement methods on it
impl dyn Print + 'static {
fn print_traitobject(&self) {
println!("from trait object");
}
}
impl Print for Point {
fn print(&self) {
println!("x: {}, y: {}, z: {}", self.x, self.y, self.z);
}
}
// static dispatch (compile time): compiler must know specific versions
// at compile time generates a version for each type
// compiler will use monomorphization to create different versions of the function
// for each type. However, because they can be inlined, it generally has a faster runtime
// compared to dynamic dispatch
fn static_dispatch<T: Print>(point: &T) {
point.print();
}
// dynamic dispatch (run time): compiler doesn't need to know specific versions
// at compile time because it will use a pointer to the data and the vtable.
// The vtable contains pointers to all the different different function implementations.
// Because it has to do lookups at runtime it is generally slower compared to static dispatch
// point_trait_obj is a trait object
fn dynamic_dispatch(point_trait_obj: &(dyn Print + 'static)) {
point_trait_obj.print();
point_trait_obj.print_traitobject();
}
fn main() {
let point = Point { x: 1, y: 2, z: 3 };
// On the next line the compiler knows that the generic type T is Point
static_dispatch(&point);
// This function takes any obj which implements Print trait
// We could, at runtime, change the specfic type as long as it implements the Print trait
dynamic_dispatch(&point);
}