Question

我是java web应用程序开发的新手，并试图在mySQL数据库中使用hibernate保存记录，但在尝试保存记录时遇到错误。

POJO班

package defaultpackage;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;


public class Sirs  implements java.io.Serializable {


 private int sirsid;
 private String sirsDescription;
 private String submitter;

public Sirs() {
}


public Sirs(int sirsid) {
    this.sirsid = sirsid;
}
public Sirs(int sirsid, String sirsDescription, String submitter) {
   this.sirsid = sirsid;
   this.sirsDescription = sirsDescription;
   this.submitter = submitter;
}
@GeneratedValue(strategy=GenerationType.TABLE)
public int getSirsid() {
    return this.sirsid;
}

public void setSirsid(int sirsid) {
    this.sirsid = sirsid;
}
public String getSirsDescription() {
    return this.sirsDescription;
}

public void setSirsDescription(String sirsDescription) {
    this.sirsDescription = sirsDescription;
}
public String getSubmitter() {
    return this.submitter;
}

public void setSubmitter(String submitter) {
    this.submitter = submitter;
}
}

sirs.hbm.xml文件

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<!-- Generated 12 Dec, 2014 1:32:06 PM by Hibernate Tools 4.3.1 -->
<hibernate-mapping>
<class name="defaultpackage.Sirs" table="sirs" catalog="sirsdb" optimistic-lock="version">
    <id name="sirsid" type="int">
        <column name="SIRSID" />
        <generator class="assigned" />
    </id>
    <property name="sirsDescription" type="string">
        <column name="`SIRS Description`" length="45" />
    </property>
    <property name="submitter" type="string">
        <column name="Submitter" length="45" />
    </property>
</class>
</hibernate-mapping>

的hibernate.cfg.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">       
<hibernate-configuration>
<session-factory>
<property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/sirsdb?
zeroDateTimeBehavior=convertToNull</property>             
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password">root</property>
<property name="show_sql">true</property>
  <property name="hibernate.hbm2ddl.auto">update</property>
<mapping resource="defaultpackage/Sirs.hbm.xml"/>
</session-factory>
</hibernate-configuration>

addsirs.jsp代码

<%@page import="defaultpackage.Sirs"%>
<!-- A jsp to insert record through hibernate -->
<%@ page import="java.util.*,org.hibernate.*,org.hibernate.cfg.*,
org.hibernate.boot.registry.StandardServiceRegistryBuilder,
org.hibernate.service.ServiceRegistry, org.hibernate.SessionFactory" %>
<%!
int sirsid;String submitter;String sirsDescription; Session session1 = null;
%>
<body>
<%
String num1=request.getParameter("t1");
if(num1 != null)
{
out.println("<h1>Data</h1>");
sirsid=Integer.parseInt(num1);
sirsDescription=request.getParameter("t2");
submitter=request.getParameter("t3");
try
{
Configuration conf = new Configuration().configure("hibernate.cfg.xml");

ServiceRegistry sr = new
StandardServiceRegistryBuilder().applySettings(conf.getProperties()).build();

SessionFactory sf = conf.buildSessionFactory(sr);

Session session1 = sf.openSession();
Sirs e=new Sirs(sirsid,sirsDescription,submitter);
Transaction transaction = session1.beginTransaction();
session1.save(e);
//session1.flush();
transaction.commit();
session1.close();
out.println("<h1>Data Inserted Successfully</h1>");
}
catch(Exception e)
{
System.out.println("e="+e.getMessage());
}
}
%>

<form>
<table width="352" border="1">
<tr>
  <th>SIRS ID</th>
  <td><input name="t1" type="text"></td>
</tr>
<tr>
  <th> Description </th>
  <td><input name="t2" type="text"></td>
</tr>
<tr>
  <th> Submitter </th>
  <td><input name="t3" type="text"></td>
</tr>
<tr>
  <th colspan="2"><input type="submit"value="Submit" >
  </th>
</tr>
</table>
</form>
</body>
</html>

web.xml文件

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" 
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-   
app_3_1.xsd">
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>*.htm</url-pattern>
</servlet-mapping>
<session-config>
    <session-timeout>
        30
    </session-timeout>
</session-config>
<welcome-file-list>
    <welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>
</web-app>

Glassfish服务器窗口

Info:   Hibernate: insert into sirsdb.sirs (`SIRS Description`, Submitter, SIRSID) values (?, ?,      
?)
WARN:   SQL Error: 1205, SQLState: 41000
ERROR:   Lock wait timeout exceeded; try restarting transaction
Info:   HHH000010: On release of batch it still contained JDBC statements
Info:   e=could not execute statement

请帮助!!

Answer 1

您是否可以检查您的应用程序的先前实例是否仍在运行，或者是否在交易过程中打开了数据库浏览工具？打开终端浏览＆amp;在同一张桌子could be the root cause上工作。您也可以在mysql命令行上执行show full processlist。这些通常会显示锁定查询的完整sql。
如果这没有帮助，请确认在更新超时后重新启动了mysql服务。
使用最大池大小为10的休眠连接池。这是example如何做到这一点。

获取WARN：SQL错误：1205，SQLState：41000错误：超出锁定等待超时;尝试重新启动事务。使用休眠保存记录

1 个答案: