Question

我正在尝试将我的注册表单数据插入到我的表中但由于某种原因没有插入任何内容而且我没有收到错误。

有人可以告诉我我在哪里出错，因为我是php和MySQL的新手，提前谢谢。

我的config.php文件保存了我的连接：

<?php
$host="localhost";
$username="mark";
$password="password";
$db_name="hewden1";
$conn = mysql_connect("$host", "$username", "$password") or die("Could Not Connect to Server");
$db = mysql_select_db("$db_name")or die("Cannot Connect the Database"); 
?>

这是我的注册表格html：

<form name="test" action="validation/signup_process.php" method="post">
<input type="text" name="compname" class="login_form" placeholder="Company or Trading Name">
<br>
<input type="text" name="contactname" class="login_form" placeholder="Contact Name"><br><br><br>
<input type="text" name="emailaddress" class="login_form" placeholder="Email Address">
<br>
 <input type="text" name="password1" class="login_form" placeholder="Password">
 <input type="text" name="password2" class="login_form" placeholder="Confirm Password"><br>

 <input type="submit" name="submit" value="Register" class="buttons">
</form>

我的php / MySQL代码：

<?php 
session_start();
include("config.php");
//retrieve our data from POST
$compname = $_POST['compname'];
$contactname = $_POST['contactname'];
$username = $_POST['emailaddress'];
$password1 = $_POST['password1'];
$password2 = $_POST['password2'];

if($password1 != $password2) {
$_SESSION['message2'] = '<div id="message_box2"><div class="boxclose" id="boxclose" onclick="this.parentNode.parentNode.removeChild(this.parentNode);"></div><h23>Ooops!</h23><p>The Password&#39;s did not match.</p> </div>';
header("location:..\sign-up.php");

}else{
if(strlen($username) > 30) {
$_SESSION['message2'] = '<div id="message_box2"><div class="boxclose" id="boxclose" onclick="this.parentNode.parentNode.removeChild(this.parentNode);"></div><h23>Ooops!</h23><p>The Username you have selected is incorrect.</p> </div>';
header("location:..\sign-up.php");

}else{

$hash = hash('sha256', $password1);

function createSalt(){
$text = md5(uniqid(rand(), true));
return substr($text, 0, 3); }
$salt = createSalt();
$password = hash('sha256', $salt . $hash);

$username = mysql_real_escape_string($username);
$query = "INSERT INTO supplier_pre_sign (contactname, company_name, supplier_email, password, date, user_type) VALUES ('$contactname','$compname','$username', '$salt', now(), 'visitor');" or die(mysql_error());

echo "eveything ok";

} }?>

Answer 1

使用此

$host="localhost";
$username="mark";
$password="password";
$db_name="hewden1";
$conn = mysql_connect($host, $username, $password) or die("Could Not Connect to Server");
$db = mysql_select_db($db_name)or die("Cannot Connect the Database");

//插入查询

$query = "INSERT INTO supplier_pre_sign (contactname, company_name, supplier_email, password, date, user_type) VALUES ('$contactname','$compname','$username', '$salt', now(), 'visitor');" or die(mysql_error());
$res = mysql_query($query);

Answer 2

您忘记执行查询。您需要执行查询才能插入数据库。

试试这个：

    <?php 
    session_start();
    include("config.php");
    //retrieve our data from POST
    $compname = $_POST['compname'];
    $contactname = $_POST['contactname'];
    $username = $_POST['emailaddress'];
    $password1 = $_POST['password1'];
    $password2 = $_POST['password2'];

    if($password1 != $password2) {
    $_SESSION['message2'] = '<div id="message_box2"><div class="boxclose" id="boxclose" onclick="this.parentNode.parentNode.removeChild(this.parentNode);"></div><h23>Ooops!</h23><p>The Password&#39;s did not match.</p> </div>';
    header("location:..\sign-up.php");

    }else{
    if(strlen($username) > 30) {
    $_SESSION['message2'] = '<div id="message_box2"><div class="boxclose" id="boxclose" onclick="this.parentNode.parentNode.removeChild(this.parentNode);"></div><h23>Ooops!</h23><p>The Username you have selected is incorrect.</p> </div>';
    header("location:..\sign-up.php");

    }else{

    $hash = hash('sha256', $password1);

    function createSalt(){
    $text = md5(uniqid(rand(), true));
    return substr($text, 0, 3); }
    $salt = createSalt();
    $password = hash('sha256', $salt . $hash);

    $username = mysql_real_escape_string($username);
    $query = "INSERT INTO supplier_pre_sign (contactname, company_name, supplier_email, password, date, user_type) VALUES ('$contactname','$compname','$username', '$salt', now(), 'visitor')";
    mysql_query($query); //You forgot to add this line
    echo "eveything ok";

    } }?>

Answer 3

您的插入查询位于函数中，我看不到它被调用然后，您的$query也没有被执行在创建查询的行之后添加mysql_query($query);。

Answer 4

仅限嘿此更改

$query = "INSERT INTO supplier_pre_sign (contactname, company_name, supplier_email, password, date, user_type) VALUES ($contactname,$compname,$username, $salt, now(), 'visitor');" or die(mysql_error());

我认为它会正常工作

结帐类似的答案

Inserting $variable or $_POST value into mysql table

Answer 5

试试这个：

<?php 
session_start();
include("config.php");
//retrieve our data from POST
$compname = $_POST['compname'];
$contactname = $_POST['contactname'];
$username = $_POST['emailaddress'];
$password1 = $_POST['password1'];
$password2 = $_POST['password2'];

if($password1 != $password2) {
$_SESSION['message2'] = '<div id="message_box2"><div class="boxclose" id="boxclose" onclick="this.parentNode.parentNode.removeChild(this.parentNode);"></div><h23>Ooops!</h23><p>The Password&#39;s did not match.</p> </div>';
header("location:..\sign-up.php");

}elseif($username != "something") {  //Write a code in the (). 
if(strlen($username) > 30) {
$_SESSION['message2'] = '<div id="message_box2"><div class="boxclose" id="boxclose" onclick="this.parentNode.parentNode.removeChild(this.parentNode);"></div><h23>Ooops!</h23><p>The Username you have selected is incorrect.</p> </div>';
header("location:..\sign-up.php");

}else{

$hash = hash('sha256', $password1);

function createSalt(){
$text = md5(uniqid(rand(), true));
return substr($text, 0, 3); }
$salt = createSalt();
$password = hash('sha256', $salt . $hash);

$username = mysql_real_escape_string($username);
$query = "INSERT INTO supplier_pre_sign (contactname, company_name, supplier_email, password, date, user_type) VALUES ($contactname,$compname,$username, $salt, now(), 'visitor');" or die(mysql_error());

$res = mysql_query($query);

if($res){echo "inserted";} else{ mysql_error($res) }

    echo "eveything ok";

} }?>

mysql将值插入表中？

5 个答案: