在我的用例中,我想删除与特定testEntity(从外部作为参数传递)和任何类型LabelTestEntity
的标签相关联的SUB_LABEL
的所有条目。要做到这一点,我使用grails executeUpdate()
方法,在我看来应该是这样的:
LabelTestEntity.executeUpdate("DELETE FROM LabelTestEntity WHERE testEntity= :TEST and label.labelType= :TYP",
[TEST: testEntity, TYP: Label.Type.SUB_LABEL])
不幸的是,这会导致SQL语法错误:
Error |
2014-12-17 16:14:06,130 [http-nio-8080-exec-2] ERROR util.JDBCExceptionReporter - Syntax error in SQL statement "DELETE FROM LABEL_TEST_ENTITY CROSS[*] JOIN LABEL LABEL1_ WHERE TEST_ENTITY_NAME=? AND TEST_ENTITY_SPEC_PATH=? AND TEST_ENTITY_SPEC_FILE_NAME=? AND LABEL_TYPE=? "; SQL statement:
delete from label_test_entity cross join label label1_ where test_entity_name=? and test_entity_spec_path=? and test_entity_spec_file_name=? and label_type=? [42000-176]
Error |
2014-12-17 16:14:06,210 [http-nio-8080-exec-2] ERROR errors.GrailsExceptionResolver - JdbcSQLException occurred when processing request: [POST] /cartoapp/mapping/groupedReassignOfSubLabels
Syntax error in SQL statement "DELETE FROM LABEL_TEST_ENTITY CROSS[*] JOIN LABEL LABEL1_ WHERE TEST_ENTITY_NAME=? AND TEST_ENTITY_SPEC_PATH=? AND TEST_ENTITY_SPEC_FILE_NAME=? AND LABEL_TYPE=? "; SQL statement:
delete from label_test_entity cross join label label1_ where test_entity_name=? and test_entity_spec_path=? and test_entity_spec_file_name=? and label_type=? [42000-176]. Stacktrace follows:
org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "DELETE FROM LABEL_TEST_ENTITY CROSS[*] JOIN LABEL LABEL1_ WHERE TEST_ENTITY_NAME=? AND TEST_ENTITY_SPEC_PATH=? AND TEST_ENTITY_SPEC_FILE_NAME=? AND LABEL_TYPE=? "; SQL statement:
delete from label_test_entity cross join label label1_ where test_entity_name=? and test_entity_spec_path=? and test_entity_spec_file_name=? and label_type=? [42000-176]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:344)
at org.h2.message.DbException.get(DbException.java:178)
at org.h2.message.DbException.get(DbException.java:154)
at org.h2.message.DbException.getSyntaxError(DbException.java:190)
at org.h2.command.Parser.getSyntaxError(Parser.java:517)
at org.h2.command.Parser.prepareCommand(Parser.java:246)
到目前为止我尝试了什么:
FROM
。 结果:只是语法糖,并且总是在内部使用仅使用一个条件尝试相同的查询。
LabelTestEntity.executeUpdate("DELETE FROM LabelTestEntity WHERE testEntity= :TEST", [TEST: testEntity])
结果:此作品,无论与哪种类型的标签相关联,特定测试的所有LabelTestEntity
都会被删除。
这使我得出结论,使用AND
向WHERE
块添加第二个条件会导致语法错误。有人可以建议或有人知道 - 这里有什么问题?
---- ---- EDIT 以下是域类之间的关系:
class LabelTestEntity implements Serializable {
Label label
TestEntity testEntity
static mapping = {
id composite: ['label', 'testEntity']
}
}
class Label {
//0 FOR MAIN_LABEL 1 FOR SUB_LABEL, 2 FOR TECH_LABEL
enum Type {
MAIN_LABEL, SUB_LABEL, TECH_LABEL
private final int value;
private Type() {
this.value = ordinal();
}
}
String name
Application application
String description
Type labelType
static constraints = {
name blank: false
application blank: false
description nullable : true
}
static mapping = {
labelType enumType:"ordinal"
}
}
答案 0 :(得分:0)
因此,经过一番努力,我们发现DELETE
不支持联接,但尝试访问相关Label
实体的属性会在内部转换为联接。
解决方案是预先选择要删除的LabelTestEntity
- 然后删除这些实体。
LabelTestEntity.executeUpdate("DELETE LabelTestEntity lte "
+ "WHERE lte.id IN ( SELECT lte2.id FROM LabelTestEntity lte2 WHERE lte2.testEntity= :TEST "
+ "AND lte2.label.labelType= :TYP)", [TEST: testEntity, TYP: labelType])
为了使预选更轻量级并且仅通过ID删除,有必要删除“LabelTestEntity”的静态映射,这将改变生成ID的方式。