Swift解析错误/强制转换异常

Question

我试图在swift中解析JSON。在我的程序早期，当我说

时，它的工作正常

func connectionDidFinishLoading(connection: NSURLConnection!) {
    var err: NSError
    // throwing an error on the line below (can't figure out where the error message is)
    var jsonResult: NSDictionary = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: nil) as NSDictionary

    println(jsonResult.valueForKey("results")?.valueForKey("geometry")?.valueForKey("location")?.valueForKey("lat"))

    if(jsonResult.valueForKey("status") as String == "OK"){
        var nearestLat = jsonResult.valueForKey("results")?.valueForKey("geometry")?.valueForKey("location")?.valueForKey("lat") as [CLLocationDegrees]
        var nearestLong = jsonResult.valueForKey("results")?.valueForKey("geometry")?.valueForKey("location")?.valueForKey("lng") as [CLLocationDegrees]
        var openStatus = jsonResult.valueForKey("results")?.valueForKey("opening_hours")?.valueForKey("open_now") as [Int]
        var address = jsonResult.valueForKey("results")?.valueForKey("vicinity") as [String]
        var name = jsonResult.valueForKey("results")?.valueForKey("name") as [String]

        var boolOpen = Bool(openStatus[0])

        var nearestChipotle = NearestRestaurant(name: name[0], lat: nearestLat[0], long: nearestLong[0], address: address[0], open: boolOpen)

        println(nearestChipotle.milesToRestuarant(self.latitude, fromLong: self.longitude))
//            
//            println(nearestLat[0])
//            println(nearestLong[0])
//            println(boolOpen)
//            println(address[0])
//            println(name[0])

    }

    else if jsonResult.valueForKey("status") as String == "ZERO_RESULTS"{
        println("NO CHIPOTLE!")
    }

不能工作

if(jsonResult.valueForKey("status") as String == "OK"){

        println(jsonResult.valueForKey("rows")?.valueForKey("elements")?.valueForKey("distance")?.valueForKey("text") as String)
       //var metersTo = jsonResult.valueForKey("rows")?.valueForKey("elements")?.valueForKey("distance")?.valueForKey("value") as String
        //println(metersTo)
       //self.distanceTo = metersToMiles()
       //println(self.distanceTo)
       //self.timeTo = jsonResult.valueForKey("rows")?.valueForKey("elements")?.valueForKey("duration")?.valueForKey("text") as String

        //println(metersTo)
        //println(self.timeTo)
    }

    else if jsonResult.valueForKey("status") as String == "ZERO_RESULTS"{
        println("NO DISTANCE COMPUTED!")
    }

但是当我稍后在程序中尝试相同的方法时，我收到此错误

由此代码

引起

这是我的输出的样子。由于额外的＆＃39;（＆＃39;＆＃39;）＆＃39;看起来我赢得的第二个JSON没有被正确播放。括弧。

处理这些括号或导致它们的原因是什么？

这两个JSON信息都来自Google API