我是一个django新手,并且在更长的时间里还有一场大斗争......:/
用户可以选择设置为ForeignKey的“主要语言”。用户可以选择“其他语言”作为ManyToMany(复选框)。假设,用户选择英语作为“主要”语言,所以英语必须从“其他语言”中过滤掉......一直在搜索,并且不知道如何去做。如果没有JavaScript,这甚至可能吗?
当然,我可以在第二种形式中设置'queryset',但它会在提交后过滤对象......类似的问题是,当选定的国家/地区必须连接到正确的zipcodes时...... / p>
我非常感谢任何提示。 最好的问候。
class Country(models.Model):
enter code here
country = models.CharField(max_length=40)
active = models.BooleanField(default=True)
class Meta:
verbose_name_plural = 'Länder'
def __str__(self):
return self.country
class ZipCode(models.Model):
zipcode = models.CharField(max_length=5)
city = models.CharField(max_length=255)
active = models.BooleanField(default=False)
class Meta:
verbose_name_plural = 'Postleitzahlen'
def __str__(self):
return '{0} {1}'.format(self.zipcode, self.city)
class MainLanguage(models.Model):
language = models.CharField(verbose_name='Hauptsprache', max_length=40)
active = models.BooleanField(default=True)
class Meta:
verbose_name_plural = 'Hauptsprachen'
ordering = ['language']
def __str__(self):
return self.language
class SecondLanguage(models.Model):
language = models.CharField(verbose_name='weitere Sprachen', max_length=40)
active = models.BooleanField(default=False)
class Meta:
verbose_name_plural = 'weitere Sprachen'
ordering = ['language']
def __str__(self):
return self.language
class CustomUserprofile(models.Model):
user = models.OneToOneField(User)
name = models.CharField(verbose_name='Vorname', max_length=40,
null=True, blank=True)
country = models.ForeignKey(Country, verbose_name='Land',
null=True, blank=True)
zipcode = models.ForeignKey(ZipCode, blank=True, null=True)
main_language = models.ForeignKey(
MainLanguage, verbose_name='Hauptsprache',
null=True, blank=True)
second_language = models.ManyToManyField(
SecondLanguage, verbose_name='weitere Sprachen',
null=True, blank=True)
class UserProfileForm(forms.ModelForm):
second_language = forms.ModelMultipleChoiceField(
queryset=SecondLanguage.objects.all(),
required=False,
widget=forms.CheckboxSelectMultiple)
class Meta:
model = CustomUserprofile
exclude = ('user',)