如何释放使用此代码分配的2D指针数组:
board = new Node ** [r];
//creates a column for each element in the row
for(int i = 0; i < r; i++) {
board [i] = new Node * [c];
}
它是一个2D数组指针,对于我目前在析构函数中的内容,它指向board = line ....
Board是一个Node ***,就像它应该的那样。
答案 0 :(得分:3)
您应该按照分配的相反顺序解除分配:
for(int i = 0; i < r; i++) {
delete [] board[i];
}
delete [] board;