我坚持使用子ng-repeat slug获得父ng重复值。它没有显示任何空白的td&#39>
我做了什么
$scope.column = [column_id: "12"slug: "item6"sort: "0"status: "1"title: "Contact no"ts_datetime: "2014-12-12 12:27:50"];
$scope.column.item = [item1: "1"item2: "2"item3: "3"item4: "4"item5: "5"item6: "8"item_id: "1"status: "1"]
<table class="table table-bordered table-striped">
<thead>
<tr>
<th ng-repeat="column in columns" >{{ column.title }}</th>
</tr>
</thead>
<tbody>
<tr ng-repeat="item in listings">
<td ng-repeat="column in columns" ng-init="val = item.column.slug">{{ val }}</td>
</tr>
</tbody>
</table>
我想要的是这个。使用列的slug获取item的值。像item.column.slug
答案 0 :(得分:1)
看起来你想要使用:
<td ng-repeat="column in columns">{{item[column].slug}}</td>